The gene for tallness (T) is dominant over the gene for
shortness (t) in pea plants. A homozygous dominant pea
plant is crossed with a heterozygous pea plant, and 200
seeds are produced. Approximately how many of these seeds
can be expected to produce plants that are homozygous
dominant?
Answers were Sorted based on User's Feedback
when a homozygous tall (TT) is crossed with heterozygous
tall (Tt) they will segregate in ratio of 1:1. Thus there
would be nearly 100 seeds of each type. thus the no. of
seeds for homozygous dominant would be 100.
Homozygous Tall (TT) x Heterozygous Tall (Tt)
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TT, Tt
(1 : 1)
Is This Answer Correct ? | 9 Yes | 0 No |
Answer / mounika
1 out of 4 will be homozygous dominant as per law..so 50 out
of 200 will be homozygous dominent
Is This Answer Correct ? | 15 Yes | 7 No |
Answer / viswa
150 out of 200 seeds are to be homozygous dominant
(TT)....according to mendle laws of cross over......
Is This Answer Correct ? | 1 Yes | 10 No |
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