program to find a smallest number in an array
Answers were Sorted based on User's Feedback
Answer / suse
main()
{
int a[20],n,i,s;
scanf("%d,%d",&n,&a[i]);
s=a[0];
for(i=0;i<n;i++)
{
if(s>a[i])
{
s=a[i];
}
}
printf("the smallest number is %d",s);
}
| Is This Answer Correct ? | 5 Yes | 7 No |
Answer / kalee
// Algorithm
Add the numbers directly into a set<double> varible, while getting the values from keyboard. First element of this set will be the least integer
This is a bad answer , if memory constraint is to be taken into account
| Is This Answer Correct ? | 4 Yes | 9 No |
Answer / belsia
void main()
{
int a[10];
for(i=0;i<10;i++)
scanf("%d",&a[i]);
for(i=0;i<10;i++)
{
if(a[i]>a[i+1])
{
temp=a[i];
a[i]=a[i+1];
a[i+1]=temp;
}
}
printf("The smallest element is %d",a[0]);
getch();
}
| Is This Answer Correct ? | 7 Yes | 17 No |
Answer / atul kumar
#include<iostream.h>
void main()
{
int a, b[4]=[1,2,3,4];
a[0]=b[0];
for(i=1;i<=5;i++)
{
if(a>b[i])
{
a=b[i];
}
}
cout<<"smallest num"<<a;
}
| Is This Answer Correct ? | 7 Yes | 18 No |
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