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The circum-radius of an equilateral triangle is 8 cm. The
in-radius of the triangle is
(a) 3.25 cm
(b) 3.50 cm
(c) 4 cm
(d) 4.25 cm
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Answer / alok kr singh
A/SinA=B/SinB=c/Sin C=2R property
8/sin60=2R
therefore, 2R=8*2/sqrt3
R=8/1.71= 4.25 Ans.
| Is This Answer Correct ? | 2 Yes | 17 No |
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