What is the integral value of 1/((ax+b)pow(-8))?



What is the integral value of 1/((ax+b)pow(-8))?..

Answer / Rohan Ravi

"To calculate this integral, it would be necessary to use integration techniques such as partial fractions. However, here is a step-by-step approach to solve it: First, we can rewrite the integrand as A/(ax+b)^8 + B/(ax+b)^7 + C/(ax+b)^6 + D/(ax+b)^5 + E/(ax+b)^4 + F/(ax+b)^3 + G/(ax+b)^2 + H/ax + I. Then, we can solve for A, B, C, D, E, F, G, H, and I by using partial fractions decomposition followed by integrating each term."

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