Answer / nandkumar karlekar

Take this script and try u will get nth salary as you wish

create Table EmpTest
(
ID bigint,
Sal bigint
)
go
insert into emptest
values
(1,100)

insert into emptest
values
(2,200)

insert into emptest
values
(3,300)

insert into emptest
values
(4,400)

insert into emptest
values
(5,500)

insert into emptest
values
(6,600)
go
DECLARE @n bigint
--specify your nth salary
SET @n=3

select top 1 * from Emptest
where @n <= (select Count(*) from Emptest EE where EE.sal
>Emptest.sal)
order by sal desc

Answer / latha k

declare @N INT
SET @N = 3
SELECT *
FROM [user] AS [user]
WHERE @N = (SELECT COUNT(DISTINCT(user1.Salary))
FROM [user] AS [user1]
WHERE user.Salary <= user1.Salary
)

Answer / dilip

SELECT MIN(SALARY) FROM tablealies.Table_Name WHERE SALARY
IN (SELECT DISTINCT TOP N MAX(SALARY) FROM
tablealies.Table_Name ORDER BY SALARY DESC)

Answer / premsagar12

SELECT DISTINCT(A.SAL),ENAME FROM EMP A WHERE &N=(SELECT
COUNT(DISTINCT(B.SAL )) FROM EMP B WHERE A.SAL<=B.SAL);

Answer / dinesh

select distinct(a.salary)
from Salarydtls a
where 3= (select distinct(count(b.salary))
from salarydtls b
where a.salary<=b.salary)

ans is for third highest sal

Answer / raman sharma

For third highest salary u can use this syntax

select min(cin) from ( select distinct cin from
cws.usertable order by cin desc ) where rownum<4

Answer / bala

-- to find third highest salary from emp table
select empname,empsal from emp a where 3 = (select count(*)
from emp b where a.empsal <= b.empsal);

Answer / sysdomain

'top' will fetch only top most : ie top 5 means it will
fetch first 5 rec. After fetching rec only 'order by' is
done ie sorting is done after fetching. therefore using
'top' and 'order by' alone wont get max or min value. for
that we have to use 'distinct' before 'top' along with
'order by' (which will sort
the records before fetching).

select top 1 salary from employee where salary in (select
distinct
top n salary from employee order by salary desc)

Answer / mohd javed

BY Tested in Postgres SQL : javedcc@gmail.com

select * from tablename as aliasname where (nth)= (select
count(sal) from tablename where aliasname.sal<=sal)

Answer / ganesh prasad

all are not working properly incase repeat salary
this one is correct

select min(deptsal) from dept where deptsal in ( select
distinct top 4 deptsal from dept order by deptsal desc)

How can count the string ? for ex: If i have string like 'bhaskar' then i need like b:1 h:1 a:2 s:1 k:1 r:1 please give any idea on that

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