Answer / uday

If you are looking to retrieve only alphabet string from the
input, use below code:

str="BIBHU@#$%^^&*(sundar)(*&das"

Set r=new regexp
r.pattern="[a-z A-Z]"
r.global=true
set s=r.execute(str)
'For each letter in s
'result= letter.value&result
'Next
For i=s.count -1 to 0 step -1
Set oVal=s.item(i)
result=oVal.value&result
next
print result

To retrieve only special characters from the input use the
below regular expressions in the above code:
r.pattern="[^a-z A-Z]"
r.pattern="\W"


Thanks,
Uday
http://qtpftvideos.blogspot.com/

Answer / audi7784

Str ="a0%n1@a2&n3)d4*h"
For intval=1 to Len(Str)
StrVal = Mid(Str,intval,1)
If isNumeric (StrVal) = True Then
StrNum = StrNum&StrVal
Else
StrChar = StrChar&StrVal
End If
Next
msgbox StrNum
msgbox StrChar

Answer / nahush

str="Hello Uda543y %%^&"




Set objRegExp = new RegExp
objRegExp.pattern = "[a-z A-Z]"
objRegExp.global = true

Set matches = objRegExp.execute(str)
For each x in matches

result = result & x.value

Next


MsgBox result

Answer / qtpbibhu@gmail.com

Str="BIBHU@#$%^^&*(sundar)(*&das" how to retrieve alpha
bates and how to retrieve special characters

Answer / shekhar

a="she25bh3k"

set reg=new regexp
s1="[a-z]"

reg.pattern=s1
reg.ignorecase=true
reg.global=True

set matchs=reg.execute(a)

for each match in matchs

a= match.value
''msgbox b
str=str&a

Next
msgbox str

Answer / dinesh rathod

The special characters I have chosen are just an example. Add your ... I am assuming that by "alphabet" you mean A-Z. .... Is it possible to get 0 by subtracting two unequal floating point numbers?

Answer / nihar

str="BIBHU@#$%^^&*(sundar)(*&das"
set reg=new regexp
reg.global=true
reg.ignorecase=true
reg.pattern="[W]"
set x=reg.execute(str)
for each res in x
result=res.value&result
next
msgbox result

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