I Have A Table Like This.

Cityno Cityname Mails
1 Bangalore 8km
2 Hsr Layout 20km
3 Mejistic 30km
5 Itpl 80km
6 Hebbal 115km

I Have Data Like This

I Want O/p Like This
Distance No.ofcity
0-50km 3
51-100km 2
101-150km 4

And So On

Answers were Sorted based on User's Feedback

select range distance,count(range) no_of_city
from
(SELECT cityname,mails,
CASE WHEN MAILS BETWEEN 0 AND 50 THEN '0-50'
WHEN MAILS BETWEEN 51 AND 100 THEN '51-100'
ELSE '101-150'
END RANGE
FROM CITY1)
group by range

 Is This Answer Correct ? 20 Yes 2 No

select '0-50' distance, count(*) No.ofcity from table
where mails between 0 and 50
union
select '51-100' distance, count(*) No.ofcity from table
where mails between 51 and 100
union
select '101-150' distance, count(*) No.ofcity from table
where mails between 101 and 150

 Is This Answer Correct ? 5 Yes 1 No

data abc;
set xyz;
count=1;
length Distance\$ 10;
if mails<=50 then Distance='0-50';
else if 50 < mails <= 100 then Distance='51-100';
else if 100<mails <= 150 then Distance='101-150';
run;
proc print;
run;

proc sql;
select Distance,sum(count)as NO_OFCITY
from abc
group by Distance;
quit;

 Is This Answer Correct ? 1 Yes 0 No

SELECT R,COUNT(R) FROM
(
SELECT cityname,mail,
CASE WHEN SUBSTR(MAIL,1,INSTR(MAIL,'KM' )-1) BETWEEN 0 AND 50 THEN '0-50'
WHEN SUBSTR(MAIL,1,INSTR(MAIL,'KM' )-1) BETWEEN 51 AND 100 THEN '51-100'
ELSE '101-150' END R FROM CITY) GROUP BY R;

 Is This Answer Correct ? 1 Yes 0 No

SELECT DISTANCE,COUNT(*) NO_OFCITY
from
(SELECT (CASE WHEN TO_NUMBER(RTRIM(MAILS,'KM')) BETWEEN 0
AND 50 THEN '0-50'
WHEN TO_NUMBER(RTRIM(MAILS,'KM')) BETWEEN 51 AND
100 THEN '51-100'
ELSE '101-150' END) DISTANCE
FROM TEST001) A
GROUP BY DISTANCE
order by to_number(replace(DISTANCE,'-',''))

 Is This Answer Correct ? 0 Yes 0 No

SQL> select * from quest;

Cityno cityname mails
---------- -------------------- ----------
1 bangalore 8km
2 hsr layout 20km
3 mejistic 30km
5 itpl 80km
6 hebbal 115km

6 rows selected.

SQL> with data as (
2 select level as lvl,lag(level,1,0) over(order by level) as pre_lvl
3 from dual
4 where mod(level,50) = 0
5 connect by level <=150)
6 select count(cityno),pre_lvl||'-'||lvl
7 from quest
8 ,data
9 where to_number(replace(mails,'KM',0))/10 between pre_lvl and lvl
10 group by lvl,pre_lvl;

 Is This Answer Correct ? 0 Yes 0 No

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