Answer / santhoo035

#include<iostream.h>
#include<string.h>
int main()
{
int flag=0,i=0,j=0;
char ar[4]="abc" ;
char temp[4];
cout<<"Plz enter a string with size #3";
cin>>temp;
for(j=0;ar[j];j++)
{
flag=0;
for(i=0;temp[i];i++)
{
if(ar[j]==temp[i])
flag+=1;
}
if(flag==0||flag>1)
break;
}
if(flag==0||flag>1)
cout<<"Not accepted";
else
cout<<"Accepted";
}
Note:PLz convert "iostream.h" into "stdio.h" and "cout<<"
to "printf"

Answer / ew

The above is broken. If the ar[4] is "aac" rather
than "abc" it fails.

#include "stdio.h"

#define CountOf(a) (sizeof(a)/sizeof(*a))

int main(int argc, _TCHAR* argv[])
{


char data[] = "abc";
char test[CountOf(data)];

printf("Enter %d characters: ", CountOf(data)-1);
scanf("%s", test);

for (int i=0;i < CountOf(data);i++)
{
for (int j=0;j < CountOf(data);j++)
{
if (data[i] == test[j])
{
test[j] = 0;
break;
}
}
}

for (int i=0;i < CountOf(data);i++)
{

if (test[i]) {
printf("\nNot ");
break;
}
}
printf("\nAccepted");

return 1;
}

Answer / rahul shandilya

both of the solutions above given have complexity O(N^2),
i have tried to solve it in O(N).let me inform if there is
any bug or better solution .

#include<iostream>
using namespace std;
int main()
{
int a[130],a1[130];
memset(a,0,sizeof(a));
memset(a1,0,sizeof(a));
char ans[1000];
char str[]="putanystringhere";
for(int i=0;i<sizeof(str)/sizeof(char)-1;i++)
{
a[(int)str[i]]+=1;
}
cout<<"Enter any string of length
"<<sizeof(str)/sizeof(char)-1<<" :";
cin>> ans;
for(int i=0;i<sizeof(str)/sizeof(char)-1;i++)
{
a1[(int)ans[i]]+=1;
}
bool flag=true;
for(int i=0;i<sizeof(str)/sizeof(char)-1;i++)
{
if(a[(int)str[i]]!=a1[(int)str[i]])
{
flag=false;
break;
}
}
if(flag==true)
cout<<"No error";
else
cout<<"Error";
system("pause");
return 0;
}

Answer / sivan

if we ask the user to enter the second string having the
same characters as in the first string, the program
essentailly reduces to finding whether there is a
repetition in the second string. A program for this is
given below.

#include<iostream>
using namespace std;

int main()
{
char string1[10];
char string2[10];
int flag = 0;

cout<<"\n Enter the first string";
cin>>string1;
cout<<"\n Enter the second string with the same
characters as entered in string1";
cin>>string2;
for(int i = 0; i < strlen(string2); i++)
{
for(int j = i+1; j < strlen(string2) ; j++)
{
if(string2[i] == string2[j])
{
flag = 1;
break;
}
}
}

if(flag ==1)
cout<<"\n wrong";
else
cout<<"\n correct";

return 0;
}

Answer / yegullelew

My answer is O(n) - but it is done in C# sorry for C guys
public bool isAccepted(string original, string
toCompare)
{
if (original.Length != toCompare.Length)
return false;
bool[] flags = new bool[128];
for (int i = 0; i < toCompare.Length; i++)
flags[toCompare[i]] = true;
for (int i = 0; i < original.Length; i++)
if (!flags[original[i]])
return false;
return true;
}

write a c program to Create employee record by taking details like name, employee id, address and phone number. While taking the phone number, take either landline or mobile number. Ensure that the phone numbers of the employee are unique. Also display all the details

2 Answers   TCS,

main() { char a[4]="HELL"; printf("%s",a); }

3 Answers   Wipro,

Cau u say the output....?

1 Answers  

C statement to copy a string without using loop and library function..

2 Answers   Persistent, TCS,

char inputString[100] = {0}; To get string input from the keyboard which one of the following is better? 1) gets(inputString) 2) fgets(inputString, sizeof(inputString), fp)

1 Answers  

How to swap two variables, without using third variable ?

104 Answers   AB, ADP, BirlaSoft, Cisco, Cygnet Infotech, HCL, Hewitt, Honeywell, HP, IBM, Infosys, Manhattan, Microsoft, Mobius, Percept, Satyam, SofTMware, TCS, Wipro, Yamaha,

main() { printf("%d, %d", sizeof('c'), sizeof(100)); } a. 2, 2 b. 2, 100 c. 4, 100 d. 4, 4

18 Answers   HCL, IBM, Infosys, LG Soft, Satyam,

Write a program to receive an integer and find it's octal equivalent. How can i do with using while loop.

2 Answers  

void pascal f(int i,int j,int k) { printf(“%d %d %d”,i, j, k); } void cdecl f(int i,int j,int k) { printf(“%d %d %d”,i, j, k); } main() { int i=10; f(i++,i++,i++); printf(" %d\n",i); i=10; f(i++,i++,i++); printf(" %d",i); }

1 Answers  

main() { struct date; struct student { char name[30]; struct date dob; }stud; struct date { int day,month,year; }; scanf("%s%d%d%d", stud.rollno, &student.dob.day, &student.dob.month, &student.dob.year); }

1 Answers  

write a program for area of circumference of shapes

0 Answers  

void main() { int i=5; printf("%d",i++ + ++i); }

3 Answers