Write a routine that prints out a 2-D array in spiral order
Answer Posted / raghuram.a
#include<iostream.h>
#include<conio.h>
#include<stdio.h>
main()
{
int n,m,i=0,j=0,k=0,l=0,p=0,q=1,r=0,s=1,a=40,b=25,ar[100];
clrscr();
cout<<"enter n:";
cin>>n;
printf("enter array elements:");
for(m=0;m<n;m++)
scanf("%d",&ar[m]);
gotoxy(a,b);
m=0;
printf("%d",ar[m++]);
while(m<n)
{
while(i<=j)
{
i++;
a+=4;
gotoxy(a,b);
printf("%d",ar[m++]);
if(m>=n)
goto next;
}
while(k<=l)
{ k++;
b+=4;
gotoxy(a,b);
printf("%d",ar[m++]);
if(m>=n)
goto next;
}
while(p<=q)
{
p++;
a-=4;
gotoxy(a,b);
printf("%d",ar[m++]);
if(m>=n)
goto next;
}
while(r<=s)
{
r++;
b-=4;
gotoxy(a,b);
printf("%d",ar[m++]);
if(m>=n)
goto next;
}
j+=2;
l+=2;
q+=2;
s+=2;
i=0;
k=0;
p=0;
r=0;
}
next:getch();
return 0;
}
| Is This Answer Correct ? | 1 Yes | 13 No |
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