Accenture Placement Papers 27 Apr 2006 - Placement Paper
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Answer / preetha
I got placed in Accenture on the 27th Apr 2006 through campus selection.
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out of 263 of who attented the aptitude test @ 13.00 on 27th Apr of only
25 were selected.
Aptitude test was very simple. It consisted of 4 parts: Quantitative
Aptitude, Verbal, Logical Reasoning and finally Essay writing.
QA consisted of mostly questions involving venn diagrams like:
- 20 people speak french, 25 speak english, total no of people-60,5 spoke
neither french nor english...how many spoke both?...similar ones...
- if $ represents * , * represents +, + represents - , find 6$5*6+12...
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Verbal and logical reasoning were straight forward...consisting of simple
synonyms and fill in the passage with articles.
Essay writing Topic was: Govt's stand on Reservation Policies
in educational institutions.
Next round was GD: Topic: Salman Khan's Arrest was it justified.
They mainly see our communication skills. Talk something clearly and
confidently.
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Next round was HR: Questions like why Accenture and similar ones were
asked and no. of technical questions from C and C++ were also asked in HR.
Final round was Technical: asked to explain about the filestructures
project which we had in 5th sem.. Many questions from C ,C++ and Software
engineering were also asked. The questions were were direct.They are
seeing basic knowledge.
After the technical round, we were addressed by the HR team of Accenture
who announced the final results.
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May all of you get the best placements.
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INFOSYS PAPER - 24 SEP 2006 - HYDERABAD
SNAPDEAL QUESTIONS 1. A train is going at a speed of 60kmph towards Delhi and returned back at a speed of 30kmph. What is its average speed? ANS : (2*30*60)/(30+60) = 40kmph 2. How many different 4 letter words can be framed that have at least one vowel? ANS : 264 - 214 (total no of 4 digits words – no of words with no vowels) 3. Write an algorithm to find out a number from an array of numbers where only one number occurs once and rest all occurs twice. ANS : XOR all the numbers ,you will get the number with single occurrences . 4. Which among the following have the product of the distance between opposite sides of a regular polygon and it side equals one fourth of the area. A. hexagon B. octagon C. n=16 D. n=18 ANS : n=16.(area of regular polygon = apothem*perimeter/2 Apothem = distance between opposite sides/2 Area = (opp_side_dist * n * a )/4 Product of opp_side_dist and side of reg. polygon = opp_side_dist * a For n= 16 the ration becomes 1:4 5. Which of the following cannot be a relation between two variables? ANS = 4th diagram. 6.what will be the output of this program Void print (int n) { If (n>0) { printf(“hello”); print(n-1); } printf(“world”); } ANS : N times hello followed by N+1 times world. 7. Which among the following cannot be used for future prediction? ANS : 4th Diagram. 8. There are 25 horses. We have to find out the fastest 3 horses In one race maximum 5 horses can run. How many such races are required in minimum to get the result. ANS : 7 races (A. first run all horses = 5 races, eliminate 4th 5th of all races. B. Run horses who came 1st in those 5 races = 1 race , the horse coming first is the fastest Run horses a. 2nd and 3rd with the fastest horse (in first time race A) b. 2nd and 3rd coming horse in B. c. The horse who came 2nd with the horse(who came 2nd in race B) in race A You will have the fastest 3 horses.) 9. In a game of rolling dice you are given 2 dice and you have to roll them. Whatever is the outcome the player will win that many dollars. What should the game owner charge each player (optimum) so that he doesn’t have to bear any loss? ANS : $7 10. We have a function REV(“string”,m,n).This function is capable of reversing the caharacters in the string from mth location to nth location. e.g. REV(“abcd”,2,3)  the output will be acbd We need to swap a string from a position,e.g. SWAP(“abcdefg”,4)  output needs to be efgabcd. How can the REV function used do this. ANS : L = string length,N= position given in SWAP function. SWAP(“abcdefg”,4) = REV(REV(REV(“abcdefg”,N+1,L),1,N),1,L).
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