Hi..friends can anybody write the script for this question... Am having some 20

Hi..friends can anybody write the script for this question...
Am having some 20 nos of links in a web application, i want
to click some 5,13 & 17th links. So please....can anybody
give the answer....???

-->Hani<--

Question Posted / hani308@gmail.com

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Hi..friends can anybody write the script for this question... Am having some 20 nos of links in a w..

Answer / ashok kumar

Set obj_Link = Description.Create()
obj_Link("micclass").value = "Link"
Set it_Link =
Browser("micclass:=Browser").Page("micclass:=Page").ChildObjects(obj_Link)
For i = 0 to it_Link.count-1 step 2

it_Link(i).Click 'it click +2,4,6....

Next

Is This Answer Correct ?

5 Yes

1 No

Hi..friends can anybody write the script for this question... Am having some 20 nos of links in a w..

Answer / sss

thats ok
but we must use index other wise it will not work

Is This Answer Correct ?

1 Yes

0 No

Hi..friends can anybody write the script for this question... Am having some 20 nos of links in a w..

Answer / srikanthdas

Set obj = Description.Create()
obj("micclass").value = "Link"
Set x =Browser("micclass:=Browser").Page("micclass:=Page").ChildObjects(obj)
for x= 1 to x.count
if x(i)=5 OR 13 OR 17 Then
x(i).Click
end if
Next

Is This Answer Correct ?

0 Yes

0 No

Hi..friends can anybody write the script for this question... Am having some 20 nos of links in a w..

Answer / srikanth

Set obj = Description.Create()
obj("micclass").value = "Link"
Set x=
Browser("micclass:=Browser").Page("micclass:=Page").ChildObjects(obj)
msgbox x.count
for i=0 to x.count-1
if x(i)= 5 OR 13 OR 17 Then
x(i).Click
end if
Next

Is This Answer Correct ?

0 Yes

1 No

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