Answer / geeta

rowcount=b().p().webtable().rowcount()
for i=2 to rowcount
set obj_lnk=b().P().Webtable().childitem(i,j,"Link",0)
obj_lnk.click

Answer / naaz

Descriptive programming will solve this problem. You have
to write the property name and you can assign the dynamic
value of that property. The problem with descriptive
programming is, if you are using descriptive programming
for the top level object you have to use the descriptive
programing for the child objects also. But if you are using
it for child objects you dont neet to use for parent
objects.

Example of Descriptive Programming:
JavaWindow("title:="&Value12).Activate

here title is the Object Property. And Value12 is its
value. you can use dataTable also for the value

Example:
JavaWindow("title:="&DataTable
("Value",dtLocalSheet)).Activate

Answer / akshay soni

for a website
bro=""
url=""
set desco=description.create
desco("micclass").value="link"
with browser("title:=give respctive browser title name")
set lis=page("title:=give respctive browser title name").childobjects(desco)
ls=lis.count
for i=0 to lis-1 step 1
x=lis(i).getroproperty("name")
y=lis(i).getroproperty("url")
print(x&" "&y)

Answer / jyotikrushna mohapatra

I just saw an answer which has mentioned above as:

rowcount=b().p().webtable().rowcount()
for i=2 to rowcount
set obj_lnk=b().P().Webtable().childitem(i,j,"Link",0)
obj_lnk.click

but this isn't 100% appropriate code, the script may fail
why
Ex: here we are trying to click on the link through every
row of the webtable, suppose the 3rd row doesn't contain
any link then "obj_lnk.click
will fail because there is no link present in that row so
the exact and write code will be as :

rowcount=b().p().webtable().rowcount()
for i=2 to rowcount
if b().pa().webtable().childitemcount(i,j,"Link",0)<>0
then
set obj_lnk=b().P().Webtable().childitem(i,j,"Link",0)
obj_lnk.click
end if
end for

Answer / shekhar

If we know the name of the name of that link then u guyes
can follow the below code....
In the above code how are you getting the value of j(i.e
column no). We are supposed to check each and every row &
column.
so I would like to add few lines in the above code,

rowcount=B.P.Webtable().rowcount
colCount=B.P.Webtable().columncount(rowcount)

For i=1 to rowcount
For j=1 to columncount
If B.P.Webtable().ChildItemCount(i,j,"link")<>0 then
set oLink=B.P.Webtable().ChildItem(i,j."link",o)
''oLink.(your desired operation)
y=oLink.GetRoProperty("Name")
If trim(y)= trim("Name of that link") then
oLink.Click
End If
Exit for
End If
Next
Next

Answer / veda

I think with discriptive programing but i don't know how
to use that discriptive programing in this situation.

What is QTP?

3 Answers   Crea,

Which scripting language used by quicktest professional (qtp)?

0 Answers  

What is the syntax to use out of two characters. Pls anybody can give the answer.. Thanks in advance...

1 Answers   Navis,

Can anybody help me by sharing the code for checkbox in qtp using vbscript.

2 Answers  

we are submitting data one form to another form.defaultly it is time period set as 5sec. but it is taken 15sec what to do

5 Answers   Covansys,

If already everything is tested using White-Box testing, then what is the need of using Black box testing?

3 Answers  

pls help me with scripting,right from the beginning in QTP

1 Answers  

What is the quicktest professional (qtp) testing process?

0 Answers  

How to test login page by using QTP

6 Answers  

If the object property is changing very frequently, what was your approach?

2 Answers  

anyone can explain about "Smart Identification" in QTP. what is the use of "Smart Identification" ???

1 Answers  

Differences between quicktest professional (qtp) and winrunner?

0 Answers