Answer / ganapa

Say a=1 and b=1

Now a*a=a*b

a*a - b*b = a*b - b*b

a^2 - b^2 = b(a-b)

(a+b)(a-b) = b(a-b)

a+b = b

1+1 = 1

Answer / rajesh

the above method is true only when the divisor is non zero.
so the problem is absurd.
(a+b)(a-b)=b (a-b)
we can not divide (a-b) on both sides since it is zero
that is why we cannot obtain a+b=b
i hope anyone can understand what i am trying..right??

Answer / dhanwin

True method as described above

Answer / bharathi kannan

antilog of 1 is 0. Not 1

Answer / breeze-dhanasekaran

1+1/2=1

Answer / priyanka

1! + 1! =1.

Answer / r.prakash

log1=log1
log (1*1) = log1
log1 + log1 = log 1
take anti log on both sides
now we get,
1+1=1

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