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Answer / tanveer anjam
in rs notation we first give priorty no1,2,3,4 ,rules are,
the atom is given hiest priorty with hihgest atomic no ,
let there are 4 atoms H , O , C , F attatched to chiral
carbon then F gets highest priorty 1 & similarly we give
priorty to others
|Is This Answer Correct ?||22 Yes||7 No|
Answer / akash
The R S notation of isomers were introduced by robert
cahen, vladimir prelog.
It is more useful for defining the asymmetry of
biomolecules because it accounts for all asymmetric carbons
in an isomer.
if any atom or group on the asymmetric carbon is on the
right side that asymmetric carbon is called as "R"(Rectus)
if any atom or group is on the left side the asymmetric
carbon is designated as "S"(sinister).
isoleucine will have 4 stereo isomers.
|Is This Answer Correct ?||20 Yes||11 No|
Answer / lisa
First you give priorities as Tanveer Anjam said. Then the
molecule is turned, so that the atom with the lowest
priority is in the back and we face prioritys 1,2 and 3 (In
our case H is in the back because its atomic number is the
lowest). Now you check if the sequence of the prioritys
from 1 to 3 are clockwise, then it's R. If the sequence is
counter clockwise it's S.
|Is This Answer Correct ?||10 Yes||1 No|
Answer / vijay
As said by Tanveer and Lisa they r correct.But the RS notation depends on CIP rules
The rules r
1.To attain RS notation it should be chiral carbon, means all the four groups attached to the carbon should be different.
2.The lowest priority should be taken backside in wedge method and vertically in fisher method. For example in H,O,C and methyl group, 'H' is taken as lowest priority.
3.The atoms attached to the chiral carbon should be given priority 1 2 3 4 based on highest atomic number.As example given by Tanveer.
4.In case of methyl and ethyl the priority should be given to ethyl first.
5.In case of single,double and triple bonds the priority should be given in this manner triple>double>single.
For example methyl and COOH , COOH is given as first priority.
6.RS notation doesn't accounts on optical activites of a compound.
|Is This Answer Correct ?||5 Yes||3 No|
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