how to reverse a string with out using string or predefined
function,ex:string is " i love india". the output should be
like this "i evol aidni"
Answers were Sorted based on User's Feedback
Answer / karthikjanahan
Dim str,arr
str = "i love india"
strlen = len(str)
ReDim arr(strlen)
For i = strlen to 1 step -1
arr(i) = mid(str,i,1)
x = x & arr(i)
Next
msgbox x
| Is This Answer Correct ? | 10 Yes | 5 No |
Answer / rupesh
Hi Karthik,
ur script will reverse the string but not the individual
words...
output of ur script will be "aindi evol i"
| Is This Answer Correct ? | 6 Yes | 1 No |
Answer / nivas
The below given is perfect script for this Query.
Dim str
str = "i love india"
arr = split(str, " ")
for i=lbound(arr) to ubound(arr)
revStr = strreverse(arr(i))
fStr = fStr & revStr & " "
next
msgbox fStr
| Is This Answer Correct ? | 5 Yes | 0 No |
Answer / janardhan
Given sting
String str="i love india";
String s[]=str.split();
for(int i=str.length();i>0;i--)
System.out.println(s[i]);
| Is This Answer Correct ? | 5 Yes | 2 No |
Answer / praveen ponnala
hi guys
Try this
Dim MyStr, MyArray
MyStr = "I Love India"
MyArray = Split(MyStr," ")
msgbox StrReverse(MyArray (0)) &" " &StrReverse(MyArray
(1)) &" "&StrReverse(MyArray (2))
| Is This Answer Correct ? | 3 Yes | 2 No |
Answer / rajender singh
aa = "i love india"
bb = split(aa," ")
dd = ""
For i=0 to ubound(bb)
cc = StrReverse(bb(i))
dd = dd&" "&cc
Next
msgbox dd
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / sreenu
Dim str,arr
str = "i love india"
m=split(str," ")
For k=lbound(m) to ubound(m)
mystr=m(k)
strlen = len(mystr)
ReDim arr(strlen)
For i = strlen to 1 step -1
arr(i) = mid(mystr,i,1)
x = x & arr(i)
Next
x=x&" "
Next
msgbox x
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / k.chalapathirao
i cheched it , but 8it is not reverse, plz chech it once
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / ramesh
Str="I Love india"
arr1=split(Str," ")
for i=0 to ubound(arr1)
arr=arr1(i)
lenarr=len(arr)
if lenarr=1 then
sing=sing&arr&" "
End if
if lenarr<> 1 then
for j=lenarr to 1 step-1
val=mid(arr,j,1)
rev=rev&val&" "
next
end if
rev=rev&" "
next
msgbox sing&rev
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / lak
Reverse a string without using String Functons
(mid,split,len..)
str=" i love india"
Set regExpObj=new RegExp
regExpObj.pattern="[a-z A-Z]"
regExpObj.global=true
Set matches=regExpObj.execute(str)
For each letter in matches
result=letter.value&result
Next
msgbox result
| Is This Answer Correct ? | 0 Yes | 0 No |
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