Answer / karthikjanahan

Dim str,arr
str = "i love india"
strlen = len(str)
ReDim arr(strlen)
For i = strlen to 1 step -1
arr(i) = mid(str,i,1)
x = x & arr(i)
Next
msgbox x

Answer / rupesh

Hi Karthik,
ur script will reverse the string but not the individual
words...

output of ur script will be "aindi evol i"

Answer / nivas

The below given is perfect script for this Query.

Dim str
str = "i love india"
arr = split(str, " ")

for i=lbound(arr) to ubound(arr)
revStr = strreverse(arr(i))
fStr = fStr & revStr & " "
next

msgbox fStr

Answer / janardhan

Given sting
String str="i love india";
String s[]=str.split();
for(int i=str.length();i>0;i--)
System.out.println(s[i]);

Answer / praveen ponnala

hi guys

Try this

Dim MyStr, MyArray

MyStr = "I Love India"
MyArray = Split(MyStr," ")

msgbox StrReverse(MyArray (0)) &" " &StrReverse(MyArray
(1)) &" "&StrReverse(MyArray (2))

Answer / rajender singh

aa = "i love india"
bb = split(aa," ")
dd = ""
For i=0 to ubound(bb)
cc = StrReverse(bb(i))
dd = dd&" "&cc
Next

msgbox dd

Answer / sreenu

Dim str,arr
str = "i love india"

m=split(str," ")

For k=lbound(m) to ubound(m)
mystr=m(k)

strlen = len(mystr)
ReDim arr(strlen)
For i = strlen to 1 step -1
arr(i) = mid(mystr,i,1)

x = x & arr(i)

Next
x=x&" "
Next
msgbox x

Answer / k.chalapathirao

i cheched it , but 8it is not reverse, plz chech it once

Answer / ramesh

Str="I Love india"
arr1=split(Str," ")
for i=0 to ubound(arr1)
arr=arr1(i)
lenarr=len(arr)
if lenarr=1 then
sing=sing&arr&" "
End if
if lenarr<> 1 then
for j=lenarr to 1 step-1
val=mid(arr,j,1)
rev=rev&val&" "
next
end if
rev=rev&" "
next
msgbox sing&rev

Answer / lak

Reverse a string without using String Functons
(mid,split,len..)

str=" i love india"

Set regExpObj=new RegExp
regExpObj.pattern="[a-z A-Z]"
regExpObj.global=true

Set matches=regExpObj.execute(str)
For each letter in matches
result=letter.value&result
Next

msgbox result

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