Answer / balaji ganesh

#include<stdio.h>
main()
{
char s[50];
int i=0,j;
printf("enter character string:");
while((s[i]=getchar())!='\n')
{
for(j=0;j<i;j++)
if(s[j]==s[i])
i--;
i++;
}
printf("after removing the duplicates the string is:");
for(j=0;j<i;j++)
printf("%c",s[j]);
}

Answer / nallavelli srinivas

MAIN()
{ int lsu=0;
char name[50];
pf("enter the string");
sf("%S",name);

printf(name[0]);
while(name[i]!='\0')
{
if(name[i]!=lsu){pf(name[i]);
lsu=name[i];
}
}
}

Answer / sowjanya

void main()
{
int rep=0;
char ch,str[50];
printf("enter the string:"):
scanf("%s",str);
printf("enter the character:");
scanf("%s",ch);
for(int i=0;str[i]!='/0';i++)
{
if(str[i]==ch)
{
rep++;//to count character
str[i]=' ';//to delete the duplicate
}
}
printf("the character is repeated %d times",rep);
printf("now all duplicates are deleted.");
}

int x=5; printf("%d%d%d",x,x<<2,x>>2);

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When should the volatile modifier be used?

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