Raja is twice older than raghav . If Raja was 4 years
younger, raghav was 3 years older ther diff. between their
ages is 12 years
what is the sum of thier ages
Answers were Sorted based on User's Feedback
Answer / ritesh
let age of raghav is x so age of raja is 2x.
now (2x-4)-(x+3)=12
x-7=12
x=19
so age of raja is 2*19=38
and of raghav is 19
| Is This Answer Correct ? | 56 Yes | 4 No |
Answer / dhakshanya
let age of raghav is x,
so age of raja is 2x.
now,
(2x-4)-(x+3)=12
x-7=12
x=19
so age of raja is 2*19=38
and raghav is=19
hence sum of their are = 38+19=57
answer =====57
| Is This Answer Correct ? | 19 Yes | 1 No |
Answer / sruthi
let age of raja be x and age of raghav be y
given:x=2y (1)
x-4=y+3 (2)
x-y=12 (3)
soln:(2y-4)-(y+3)=12 [substituting (2) in (3)]
2y-4-y-3=12
y-7=12
y=19
x=38
x+y=57
| Is This Answer Correct ? | 17 Yes | 0 No |
Answer / nagaraju
let age of ragav=x, age of raja=2x
(2x-4)-(x+3)=12
x-7=12
x=19
raghav age is 19 and raja age is 38
so the sum is 57
| Is This Answer Correct ? | 9 Yes | 0 No |
Answer / banupriya
let us take the age of raja=2x and raghav =x
now,
raja was 4 years younger (2x-4)
raghav was 3 years older (x+3)
then (2x-4)-(x+3)=12
2x-4-x-3-12=0
x-19=0
x=19
2x=2(19)
2x=38
hence raghav age=19 and raja =38,,,, sum =57
| Is This Answer Correct ? | 6 Yes | 0 No |
Answer / gifty
let Raghav's age be x
let Raja,s age be y
given, y=2x;---------------(1)
and y-x=12;-------------(2)
substituting (1) in (2),
x=12;
y=2(x)=2(12)=24
sum=12+24=36
| Is This Answer Correct ? | 1 Yes | 4 No |
Answer / dev.roy21@gmail.com
raja=x,raghab=2x
x+4=12+3
x=11
so sum is=11+22
=33
| Is This Answer Correct ? | 7 Yes | 13 No |
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