Answer / pranay nayan

Its 2 times faster than the other train
v1*t=v2
v2*t=4*v1
solving these two,we get
v2/v1=2

Answer / binz johnsom

et v1-peed of train from bangalore to mysore(train1)
v2- speed of train from mysore to bangalore(train2)
and x be the distance from B to M
and a be the distance from bangalore till meet point
(i.e.)train1 travels a km and train2 travels x-a km
time taken by train1 to travel a=time taken by train2 to
travel x-a
a/v1=x-a/v2, v1/v2=a/x-a
time taken by train1 to travel x-a=1hr
x-a/v1=1, x-a=v1
time taken by train2 to travel a=4hrs
a/v2=4, a=4v2
therefore s1/s2=4s2/s1
s1^2=4s2^2
s1:s2=2:1
train1 speed=twice the speed of train2

Answer / kavin

Twice

Answer / a.manikandan

3 hr

Answer / sankar adhikari

one train is 3 times faster than the other train.

Pls I Send SBI Clarical Exam Model Qustion

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