Hi, Anybody could you Please tell me How to write the
script for Checking whether given number is Prime Number or
not..Thanks in Advance
Answers were Sorted based on User's Feedback
Answer / sumit
//An Extremely Efficient method.
void chkprime(int n)
{
int i=2,j=1;
for(;i<=n/i;j++,i++)
{
if (n%i == 0)
{
break;
}
}
if ( n%i != 0 )
printf("%d is prime. Comparisons: %d\n",n,j);
}
Is This Answer Correct ? | 2 Yes | 0 No |
Answer / pankaj jaju
Function IsPrime(Num)
Dim varNum, varCtr, varLimit
varLimit = Round(Num/2)
For varCtr = 2 To varLimit
varNum = Num Mod varCtr
If varNum = 0 Then
IsPrime = False
Exit For
End If
Next
If varCtr >= varLimit Then
IsPrime = True
End If
End Function
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / anwar basha
n=cint(inputbox("enter the number"))
if n=0 then
msgbox " invalid no"
end if
flag=0
for i=1 to n-1
if n mod i =0 then
falg=1
end if
exit for
next
if falg=1 then
msgbox "not a prime num"
else
msgbox "prime no"
end if
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / manu
x=inputbox("enter a number")
prime = TRUE
for i = 0 to x-1
if x mod 2 = 0 then
prime = FALSE
end if
next
if prime then
msgbox "prime number"
else
msgbox "not prime"
end if
Is This Answer Correct ? | 0 Yes | 2 No |
Answer / nisar
Dim i,num
num=CInt(InputBox("Enter the numbers to limit the
Prime:"))
i = 3
While i <= num
bIsPrime = True
j = 2
While j <= i\2 And bIsPrime
bIsPrime = i Mod j > 0
j = j + 1
Wend
If bIsPrime Then
Wscript.echo("Found a prime number: " & i)
End If
i = i + 2
Wend
Is This Answer Correct ? | 0 Yes | 7 No |
Answer / anant
boolean isPrime(int num){
if(num==0 || num==1){
System.out.println("Number should be greater than 1");
System.Exit(0);
}
if(num%2==0 || num%3==0 || num%5==0 || num%7==0)
System.out.println("Number is not prime");
else
System.out.println("Number is prime");
}
Is This Answer Correct ? | 2 Yes | 14 No |
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