Answer / sumit

//An Extremely Efficient method.
void chkprime(int n)
{
int i=2,j=1;
for(;i<=n/i;j++,i++)
{
if (n%i == 0)
{
break;
}
}

if ( n%i != 0 )
printf("%d is prime. Comparisons: %d\n",n,j);
}

Answer / pankaj jaju

Function IsPrime(Num)
Dim varNum, varCtr, varLimit
varLimit = Round(Num/2)

For varCtr = 2 To varLimit
varNum = Num Mod varCtr

If varNum = 0 Then
IsPrime = False
Exit For
End If
Next

If varCtr >= varLimit Then
IsPrime = True
End If
End Function

Answer / anwar basha

n=cint(inputbox("enter the number"))
if n=0 then
msgbox " invalid no"
end if

flag=0
for i=1 to n-1
if n mod i =0 then
falg=1
end if
exit for
next

if falg=1 then
msgbox "not a prime num"
else
msgbox "prime no"
end if

Answer / manu

x=inputbox("enter a number")

prime = TRUE
for i = 0 to x-1
if x mod 2 = 0 then
prime = FALSE
end if
next

if prime then
msgbox "prime number"
else
msgbox "not prime"
end if

Answer / nisar

Dim i,num
num=CInt(InputBox("Enter the numbers to limit the
Prime:"))
i = 3
While i <= num
bIsPrime = True
j = 2
While j <= i\2 And bIsPrime
bIsPrime = i Mod j > 0
j = j + 1
Wend
If bIsPrime Then
Wscript.echo("Found a prime number: " & i)
End If
i = i + 2
Wend

Answer / anant

boolean isPrime(int num){
if(num==0 || num==1){
System.out.println("Number should be greater than 1");
System.Exit(0);
}
if(num%2==0 || num%3==0 || num%5==0 || num%7==0)
System.out.println("Number is not prime");
else
System.out.println("Number is prime");
}

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