why we are taking 85 ml of concentrated HCl to prepare 1N
Solution
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According to this formula
Con(mL) =(M.Wt of Hcl * 100)/ (Specific Gravity of Hcl*
Purity of Hcl)
= 36.5 * 100 / 1.18 * 36 = 85.9mL
| Is This Answer Correct ? | 258 Yes | 42 No |
Answer / kizar ahamed
we should consider the density of the solution :
density= M/V
V=M/D=36.5/1.18=30.93 if purity is 100% but in the HCL ,
purity is 36% only , so
Required volume to prepare 1N solution =30.93*100/36=85ml
| Is This Answer Correct ? | 150 Yes | 26 No |
Answer / alpesh patel
Normality of Con. HCl =(Purity of Hcl * 10 * specific
gravity of HCl)/ Eq. wt. of HCl
Where 10 is multiplied to convert in normal soln.(1000 mL)
= (36 * 10 * 1.18)/36.5 = 11.64 N.(N1)
Now,N1V1 = N2V2
v1 = (1 * 1000)/11.64
= 85.9 mL
| Is This Answer Correct ? | 88 Yes | 14 No |
Answer / ponnam
FIRST WE ARE FIND OUT LAB MORMALITY=(10 X ASSAY X Wt/ml)/M.W
=(10 X 1.18 X 36)/36.5 = 11.64. THEN M1V1=N2V2 SO,V1=(1X1000)/11.64 = 85.91
| Is This Answer Correct ? | 27 Yes | 5 No |
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