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find second largest element in array w/o using sorting
techniques? use onle one for loop.
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Answer / sazzadcsedu
int max,secMax;
int A[100];
if(A[0]>A[1])
{
max=A[0];
secMax=A[1];
}
else
{
max=A[1];
secMax=A[0];
}
for(i=2;i<=length of Array;i++)
{
if (A[i]>max )
{
secMax=max;
max=A[i];
}
else if(array[i]>secMax)
{
secMax = A[i];
}
}
| Is This Answer Correct ? | 7 Yes | 7 No |
Answer / ramesh
this is to largest element in an array using one loop concept:
for(int i=0;i<=arr.length;i++)
{
if(a[i]>a[i+1])//if first position element is large we want swap that element
{
t =a[i];
a[i] =a[i+1];
a[i+1]=t;
}
printf("%d",a[i+1]);
by
97894 33227
| Is This Answer Correct ? | 1 Yes | 3 No |
Answer / k.shravan
main()
{
int a[10],min,max,temp,i;
clrscr();
printf("\n\n Enter the array=>");
for(i=0;i<5;i++)
scanf("%d",&a[i]);
min=max=a[0];
for(i=1;i<5;i++)
{
if(a[i]>max)
{
min=max;
max=a[i];
}
if(a[i]<max && a[i]>min)
{
min=a[i];
}
}
printf("%d---%d",max,min);
getch();
}
| Is This Answer Correct ? | 7 Yes | 11 No |
Answer / anamika datta
#include<stdio.h>
#include<conio.h>
void main()
{
int n[]={5,3,4};
int i,large,sec_large;
clrscr();
large=sec_large=n[0];
for(i=0;i<3;i++)
{
if(n[i]>large)
{
sec_large=large;
large=n[i];
}
}
printf("%d",sec_large);
}
getch();
| Is This Answer Correct ? | 10 Yes | 19 No |
Answer / guest
max = 2ndmax= array[0];
for (i=0;i,length;i++)
{
if (array[i]>max)
{
2ndmax=max;
max=array[i];
}
}
return 2nd max
| Is This Answer Correct ? | 40 Yes | 74 No |
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