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#include<stdio.h>
void main()
{
int a [5];
for (i=0; i<=4; i++)
printf(“%d” ,a[i]);
}
- 8 Answers
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Answers were Sorted based on User's Feedback
Answer / kalyan chukka
Here it shows i is undefined Symbol.So if declare i as
integer then it prints some garbage value Because Array is
declared but elements are not inserted into the array.So
garbage value is printed on the console
| Is This Answer Correct ? | 10 Yes | 1 No |
Answer / sameer mohammed
It shows us garbage values as because the integer type
array is declared but it is not defined.
| Is This Answer Correct ? | 6 Yes | 2 No |
Answer / jayakrishna
here array a is declared but it is not initialised,but int
the printf we are printing values of array a[], so it
displays garbage values & cannot directly write i as
variable we must specify its type.
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / purnima
it gives compile time error because here the var i is not
declared .aIn c a var must be declared before is usage
| Is This Answer Correct ? | 0 Yes | 1 No |
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where does it flourished?
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