input like
2 7 8
9 5 1
7 3 6
output:2 5 6 how to find out this plz explain?
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Answer / deepanshu
supposing single column is there having values
278
951
736
sol'n :
Use transformer string function with @inrownum variable.
inputcolumn[@inrownum,1]
will give you desired o/p
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / bhavani
we can acheive this using transformer stage:
1. Check the record count using AGGREGTOR stage and have a column count
2. In the transformer initiate a loop with condition @ITERATION <=count. and loopvar = @iteration
3.if @INROWNUM = loopvar then right(left(@iteration),1) --> output value
Now the result will be 2
5
6
Let me know if this is correct.
| Is This Answer Correct ? | 0 Yes | 2 No |
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