#include <stdio.h> #define sqr(x) (x*x) int main() { int x=2; pri

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#include <stdio.h>
#define sqr(x) (x*x)
int main()
{
int x=2;
printf("value of x=%d",sqr(x+1));
}

What is the value of x?

Question Posted / mittal

16 Answers
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#include <stdio.h> #define sqr(x) (x*x) int main() { int x=2; printf("value of x..

Answer / divakar

ouput :value of x=5
bcoz sqr(x+1)=(x+1*x+1) if u substitute x=2 u will get 5
since '*' is having more priority than '+'

at the of prog if u add prinf("%d",x); u will get 2
bcoz x value is not changed

Is This Answer Correct ?

32 Yes

4 No

#include <stdio.h> #define sqr(x) (x*x) int main() { int x=2; printf("value of x..

Answer / vijaya

Is This Answer Correct ?

34 Yes

12 No

#include <stdio.h> #define sqr(x) (x*x) int main() { int x=2; printf("value of x..

Answer / gg

Ans : 5

I agree with Divakar ans & similar answers.

sqr(x+1)=x+1*x+1=2+1*2+1=5, but not 2*2+1

Is This Answer Correct ?

17 Yes

0 No

#include <stdio.h> #define sqr(x) (x*x) int main() { int x=2; printf("value of x..

Answer / bhagya

absolutely 5

Is This Answer Correct ?

16 Yes

0 No

#include <stdio.h> #define sqr(x) (x*x) int main() { int x=2; printf("value of x..

Answer / guest

i tried in pc the ans is 5

Is This Answer Correct ?

15 Yes

3 No

#include <stdio.h> #define sqr(x) (x*x) int main() { int x=2; printf("value of x..

Answer / ndarvind

5
Bcz 2+1*2+1=5

Is This Answer Correct ?

14 Yes

2 No

#include <stdio.h> #define sqr(x) (x*x) int main() { int x=2; printf("value of x..

Answer / azeem khan

Answer is 5

Is This Answer Correct ?

19 Yes

9 No

#include <stdio.h> #define sqr(x) (x*x) int main() { int x=2; printf("value of x..

Answer / pravin

sqrt(x+1)(x+1*x+1)
as x=2;result will be 2+1*2+1=5;
thank u

Is This Answer Correct ?

6 Yes

1 No

#include <stdio.h> #define sqr(x) (x*x) int main() { int x=2; printf("value of x..

Answer / jugal

Sorry guys,
my bad,
i thought it was
#define sqr(x) ((x)*(x))

the output wud be 5
but still the value of will be 2 only

Is This Answer Correct ?

2 Yes

0 No

#include <stdio.h> #define sqr(x) (x*x) int main() { int x=2; printf("value of x..

Answer / fazlur

Macro will blindly substitutes, it doesn't calculate. So
remember whenever you encounter the macro, you first
substitute the value then calculate later. Ofcourse the
answer would be 5 in this case.

Is This Answer Correct ?

2 Yes

0 No

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