sqrt(x+1)(x+1*x+1) as x=2;result will be 2+1*2+1=5; thank u

#include <stdio.h>
#define sqr(x) (x*x)
int main()
{
int x=2;
printf("value of x=%d",sqr(x+1));
}

What is the value of x?

Question Posted / pravin

Answer Posted / pravin

sqrt(x+1)(x+1*x+1)
as x=2;result will be 2+1*2+1=5;
thank u

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6 Yes

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