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#include<stdio.h>
void main()
{
int a [5];
for (i=0; i<=4; i++)
printf(ā€œ%dā€ ,a[i]);
}

Answer Posted / jayakrishna

here array a is declared but it is not initialised,but int
the printf we are printing values of array a[], so it
displays garbage values & cannot directly write i as
variable we must specify its type.

Is This Answer Correct ?    4 Yes 1 No



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