Answer / susie

Answer :

Compiler error: Cannot increment a void pointer

Explanation:

Void pointers are generic pointers and they can be used only
when the type is not known and as an intermediate address
storage type. No pointer arithmetic can be done on it and
you cannot apply indirection operator (*) on void pointers.

main() { int i; clrscr(); for(i=0;i<5;i++) { printf("%d\n", 1L << i); } } a. 5, 4, 3, 2, 1 b. 0, 1, 2, 3, 4 c. 0, 1, 2, 4, 8 d. 1, 2, 4, 8, 16

4 Answers   HCL,

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#include<stdio.h> void fun(int); int main() { int a; a=3; fun(a); printf("\n"); return 0; } void fun(int i) { if(n>0) { fun(--n); printf("%d",n); fun(--n); } } the answer is 0 1 2 0..someone explain how the code is executed..?

1 Answers   Wipro,

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Extend the sutherland-hodgman clipping algorithm to clip three-dimensional planes against a regular paralleiepiped

1 Answers   IBM,

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#include <stdio.h> main() { char * str = "hello"; char * ptr = str; char least = 127; while (*ptr++) least = (*ptr<least ) ?*ptr :least; printf("%d",least); }

1 Answers  

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main() { int i=400,j=300; printf("%d..%d"); }

3 Answers  

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Write a single line c expression to delete a,b,c from aabbcc

2 Answers   Microsoft,

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x=2 y=3 z=2 x++ + y++; printf("%d%d" x,y);

2 Answers  

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Write a program to model an exploding firecracker in the xy plane using a particle system

0 Answers   HCL,

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const int perplexed = 2; #define perplexed 3 main() { #ifdef perplexed #undef perplexed #define perplexed 4 #endif printf("%d",perplexed); } a. 0 b. 2 c. 4 d. none of the above

1 Answers   emc2, HCL,

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main ( ) { static char *s[ ] = {“black”, “white”, “yellow”, “violet”}; char **ptr[ ] = {s+3, s+2, s+1, s}, ***p; p = ptr; **++p; printf(“%s”,*--*++p + 3); }

1 Answers  

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main() { char name[10],s[12]; scanf(" \"%[^\"]\"",s); } How scanf will execute?

2 Answers  

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main() { int i=-1,j=-1,k=0,l=2,m; m=i++&&j++&&k++||l++; printf("%d %d %d %d %d",i,j,k,l,m); }

1 Answers  

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