Answer / susie

Answer :

i = -1, -i = 1

Explanation:

-i is executed and this execution doesn't affect the value
of i. In printf first you just print the value of i. After
that the value of the expression -i = -(-1) is printed.

print a semicolon using Cprogram without using a semicolon any where in the C code in ur program!!

35 Answers   Tata Elxsi, TCS, VI eTrans,

---

main() { int a=2,*f1,*f2; f1=f2=&a; *f2+=*f2+=a+=2.5; printf("\n%d %d %d",a,*f1,*f2); }

6 Answers  

---

#include<stdio.h> main() { struct xx { int x=3; char name[]="hello"; }; struct xx *s=malloc(sizeof(struct xx)); printf("%d",s->x); printf("%s",s->name); }

1 Answers   TCS,

---

main() { int i=-1; +i; printf("i = %d, +i = %d \n",i,+i); }

1 Answers  

---

write a simple calculator c program to perform addition, subtraction, mul and div.

0 Answers   United Healthcare, Virtusa,

---

What is the hidden bug with the following statement? assert(val++ != 0);

1 Answers  

---

Write a function to find the depth of a binary tree.

13 Answers   Adobe, Amazon, EFI, Imagination Technologies,

---

How can u say that a given point is in a triangle? 1. with the co-ordinates of the 3 vertices specified. 2. with only the co-ordinates of the top vertex given.

1 Answers  

---

char *someFun() { char *temp = “string constant"; return temp; } int main() { puts(someFun()); }

1 Answers  

---

main() { int i; i = abc(); printf("%d",i); } abc() { _AX = 1000; }

2 Answers  

---

main() { extern int i; { int i=20; { const volatile unsigned i=30; printf("%d",i); } printf("%d",i); } printf("%d",i); } int i;

1 Answers  

---

void main() { static int i; while(i<=10) (i>2)?i++:i--; printf(“%d”, i); }

2 Answers  

---