main()
{
char string[]="Hello World";
display(string);
}
void display(char *string)
{
printf("%s",string);
}
Answers were Sorted based on User's Feedback
Answer / susie
Answer :
Compiler Error : Type mismatch in redeclaration of
function display
Explanation :
In third line, when the function display is
encountered, the compiler doesn't know anything about the
function display. It assumes the arguments and return types
to be integers, (which is the default type). When it sees
the actual function display, the arguments and type
contradicts with what it has assumed previously. Hence a
compile time error occurs.
| Is This Answer Correct ? | 21 Yes | 3 No |
Answer / pratibha
this problem of type mismatching can be solved by declaring display function as a first line inside main() so that compiler will know that display is of type void and then it will resolve type mismatch while encountering calling function of display.
| Is This Answer Correct ? | 0 Yes | 0 No |
void main() { char a[]="12345\0"; int i=strlen(a); printf("here in 3 %d\n",++i); }
write a c program to Create a registration form application by taking the details like username, address, phone number, email along with password and confirm password (should be same as password).Ensure that the password is of 8 characters with only numbers and alphabets. Take such details for 5 users and display the details. In place of password display “****”. (Use Structures).
0 Answers CDAC, College School Exams Tests,
what is the output of the below program & why ? #include<stdio.h> void main() { int a=10,b=20,c=30; printf("%d",scanf("%d%d%d",&a,&b,&c)); }
main() { char a[4]="HELLO"; printf("%s",a); }
void main() { int c; c=printf("Hello world"); printf("\n%d",c); }
Write a Program in 'C' To Insert a Unique Number Only. (Hint: Just Like a Primary Key Numbers In Database.) Please Some One Suggest Me a Better Solution for This question ??
main() { int x=5; clrscr(); for(;x==0;x--) { printf("x=%d\n”", x--); } } a. 4, 3, 2, 1, 0 b. 1, 2, 3, 4, 5 c. 0, 1, 2, 3, 4 d. none of the above
¦void main() ¦{ ¦int i=10,j; ¦ j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-30 but in same question if we write as- ¦void main() ¦{ ¦int i=10; ¦ int j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-33 why output is changed from 30 to 33. Can any body answer...
Write a C program to print look and say sequence? For example if u get the input as 1 then the sequence is 11 21 1211 111221 312211 12112221 .......(it counts the no. of 1s,2s etc which is in successive order) and this sequence is used in run-length encoding.
main() { char c=' ',x,convert(z); getc(c); if((c>='a') && (c<='z')) x=convert(c); printf("%c",x); } convert(z) { return z-32; }
main() { int i = 257; int *iPtr = &i; printf("%d %d", *((char*)iPtr), *((char*)iPtr+1) ); }
#define DIM( array, type) sizeof(array)/sizeof(type) main() { int arr[10]; printf(“The dimension of the array is %d”, DIM(arr, int)); }