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main()
{
extern int i;
i=20;
printf("%d",sizeof(i));
}
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Answer Posted / susie
Answer :
Linker error: undefined symbol '_i'.
Explanation:
extern declaration specifies that the variable i is defined
somewhere else. The compiler passes the external variable to
be resolved by the linker. So compiler doesn't find an
error. During linking the linker searches for the definition
of i. Since it is not found the linker flags an error.
| Is This Answer Correct ? | 22 Yes | 4 No |
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