Answer / srinivasu

By default int is declared as unsigned integer.It's range is
0 to 65535.Signed integer range is -32767 to 32768.
A variable declared as Unsigned int doesn't holds a negative
value whereas a signed integer does.So signed and unsigned
integer doesn't differ in the range, but in the kind of
value it holds.

What is the output for the program given below typedef enum errorType{warning, error, exception,}error; main() { error g1; g1=1; printf("%d",g1); }

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#include<stdio.h> main() { struct xx { int x; struct yy { char s; struct xx *p; }; struct yy *q; }; }

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char *someFun1() { char temp[ ] = “string"; return temp; } char *someFun2() { char temp[ ] = {‘s’, ‘t’,’r’,’i’,’n’,’g’}; return temp; } int main() { puts(someFun1()); puts(someFun2()); }

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Is the following code legal? struct a { int x; struct a *b; }

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main() { int y; scanf("%d",&y); // input given is 2000 if( (y%4==0 && y%100 != 0) || y%100 == 0 ) printf("%d is a leap year"); else printf("%d is not a leap year"); }

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union u { union u { int i; int j; }a[10]; int b[10]; }u; main() { printf("\n%d", sizeof(u)); printf(" %d", sizeof(u.a)); // printf("%d", sizeof(u.a[4].i)); } a. 4, 4, 4 b. 40, 4, 4 c. 1, 100, 1 d. 40 400 4

3 Answers   HCL,

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void main() { char ch; for(ch=0;ch<=127;ch++) printf(“%c %d \n“, ch, ch); }

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Is the following code legal? struct a { int x; struct a b; }

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How to read a directory in a C program?

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main() { int i=_l_abc(10); printf("%d\n",--i); } int _l_abc(int i) { return(i++); }

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#include<stdio.h> main() { struct xx { int x=3; char name[]="hello"; }; struct xx *s; printf("%d",s->x); printf("%s",s->name); }

3 Answers   Hexaware,

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#define assert(cond) if(!(cond)) \ (fprintf(stderr, "assertion failed: %s, file %s, line %d \n",#cond,\ __FILE__,__LINE__), abort()) void main() { int i = 10; if(i==0) assert(i < 100); else printf("This statement becomes else for if in assert macro"); }

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