Answer / srinivasu

By default int is declared as unsigned integer.It's range is
0 to 65535.Signed integer range is -32767 to 32768.
A variable declared as Unsigned int doesn't holds a negative
value whereas a signed integer does.So signed and unsigned
integer doesn't differ in the range, but in the kind of
value it holds.

Write, efficient code for extracting unique elements from a sorted list of array. e.g. (1, 1, 3, 3, 3, 5, 5, 5, 9, 9, 9, 9) -> (1, 3, 5, 9).

13 Answers   Intel, Microsoft, TCS,

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what will be the output of this program? void main() { int a[]={5,10,15}; int i=0,num; num=a[++i] + ++i +(++i); printf("%d",num); }

3 Answers   Wipro,

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How will you print % character? a. printf(“\%”) b. printf(“\\%”) c. printf(“%%”) d. printf(“\%%”)

4 Answers   HCL,

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create a C-code that will display the total fare of a passenger of a taxi if the driver press enter,the timer will stop. Every 10 counts is 2 pesos. Initial value is 25.00

0 Answers   Microsoft,

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main() { unsigned int i=65000; while(i++!=0); printf("%d",i); }

1 Answers  

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int a = 10 + 10 .... ,... A = A * A What would be the value of A? The answer is 120!! Could anyone explain this to me.

2 Answers   Bosch, eInfochips, HCL, IHCL,

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main() { int i=10; void pascal f(int,int,int); f(i++,i++,i++); printf(" %d",i); } void pascal f(integer :i,integer:j,integer :k) { write(i,j,k); }

1 Answers  

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main() { char s[ ]="man"; int i; for(i=0;s[ i ];i++) printf("\n%c%c%c%c",s[ i ],*(s+i),*(i+s),i[s]); }

1 Answers   DCE,

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Give a oneline C expression to test whether a number is a power of 2?

25 Answers   EA Electronic Arts, Google, Motorola,

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#define FALSE -1 #define TRUE 1 #define NULL 0 main() { if(NULL) puts("NULL"); else if(FALSE) puts("TRUE"); else puts("FALSE"); }

1 Answers  

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How do I write a program to print proper subset of given string . Eg :input: abc output:{},{a},{b},{c},{a,b},{a,c},{b,c}, {a,b,c}.I desperately need this program please mail me to saravana6m@gmail.com

11 Answers   Deshaw, Infosys,

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main( ) { int a[ ] = {10,20,30,40,50},j,*p; for(j=0; j<5; j++) { printf(“%d” ,*a); a++; } p = a; for(j=0; j<5; j++) { printf(“%d ” ,*p); p++; } }

1 Answers  

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