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main()
{
int i, j, *p;
i = 25;
j = 100;
p = &i; // Address of i is assigned to pointer p
printf("%f", i/(*p) ); // i is divided by pointer p
}
a. Runtime error.
b. 1.00000
c. Compile error
d. 0.00000
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Answer Posted / rk
d) it will print 0.0000.
If we typecast the result to float as shown below then
expected output will be printed(i.e. 1.0000)
printf("%f",(float) i/(*p) ); // i is divided by pointer p
| Is This Answer Correct ? | 8 Yes | 0 No |
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