Answer / monty

#include<stdio.h>
#include<conio.h>
void main()
{
int a,b;
for(a=1;a<10;a++)
{
for(b=1;b<10;b++)
{
if((a==2 && b==5) ||
(a==3 && (b==4 || b==5 || b==6) )
||
(a==4 && (b>=3 && b<=7) )
||
(a==5 && (b>=2 && b<=8) )
||
(a==6 && (b>=3 && b<=7) )
||
(a==7 && (b==4 || b==5 || b==6) )
||
(a==8 && b==5))
printf("-");
else
printf("*");
}
printf("\n");
}
getch();
}

Answer / vignesh1988i

sorry i have done a small mistake ..... this is correct

#include<stdio.h>
#include<conio.h>
void main()
{
int n,i,j,k;
printf("enter the no. of lines :");
scanf("%d",&n);
for(i=1;i<=(n*2-1);i++)
{
if(!(i^1)|| !(i^(n*2-1)))
{
for(j=1;j<=(n*2-1);j++)
printf("*");
}
else
{
if(i<=n)
{
for(j=1;j<=n-i;j++)
printf("*");
for(k=1;k<(2*(i-1));k++)
printf(" ");
for(j=n-i;j>=0;j--)
printf("*");
if(i==n)
{
k--;
m=k;
}
}
else
{
for(j=1;j<=(i-n+1);j++)
printf("*");
for(j=k;k<=k-n-1;k++)
printf(" ");
k-=2;
for(j=i-n+1;j>0;j--)
printf("*");
}
}
getch();
}

Answer / vignesh1988i

#include<stdio.h>
#include<conio.h>
void main()
{
int n,i,j,k;
printf("enter the no. of lines :");
scanf("%d",&n);
for(i=1;i<=(n*2-1);i++)
{
if(!(i^1)|| !(i^(n*2-1)))
{
for(j=1;j<=(n*2-1);j++)
printf("*");
}
else
{
if(i<=n)
{
for(j=1;j<=n-i;j++)
printf("*");
for(k=1;k<(2*i);k++)
printf(" ");
for(j=n-i;j>=0;j--)
printf("*");
}
else
{
for(j=1;j<=(i-n+1);j++)
printf("*");
for(j=k-3;k<=(2*n-1);k++)
printf(" ");
for(j=i-n+1;j>0;j--)
printf("*");
}
}
getch();
}


i think this may work

thank u

Answer / prakash

int main()
{
int i, j, star, space, n, middle;

printf("Enter the max. number of stars in a line:");
scanf("%d", &n);
printf("Output:\n");

star = n/2;
space = 1;
middle = n/2 + 1;

for (j = 1; j <= n; j++)
printf("*");
printf("\n");

for (i = 2; i <= (n - 1); i++)
{
for (j = 1; j <= n; j++)
{
if ((j >= (star + 1)) &&
(j <= (star + space)))
{
printf(" ");
}
else
{
printf("*");
}
}

// calculate a and b
if (i < middle)
{
star -= 1;
space += 2;
}
else
{
star += 1;
space -= 2;
}

printf("\n");
}

for (j = 1; j <=n; j++)
printf("*");
printf("\n");

return 0;
}

what is the Output? int a=4 b=3; printf("%d%d%d%d%d%d",a++,++a,a++,a++,++a,a++); printf("%d%d%d%d%d%d",b--,b--,--b,b--,--b,--b);

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