The LCM of two positive nos is 168 and their product is 504.
what is the difference in their squares?
A. 175 B.216 C.9 D.135
Answers were Sorted based on User's Feedback
Answer / aashima
Hi All,
The ans of this question 135.
504=2*2*2*3*3*7=8*3*3*7=24*21
168=2*2*2*3*7
it means 3 will come in both the numbers as 3 is coming
once in LCM but coming as 9 in product.
so possible numbers are 24 and 21.
so diff of products is 24*24-21*21=135
Is This Answer Correct ? | 66 Yes | 3 No |
Answer / prasun bose
let the numbers be a and b
so by question---ab=504 the product
and LCM= ab/common factor=168
so common factor=ab/168 =504/168 =3
factors of LCM 168=2,2,2,3,7
so taking 3 on both side,we have
2,2,2and3 is one nunber and the other is
3,and 7 . so the numbers are 24 and 21
now the difference of the square of these nunbers
is a2-b2=(a+b)(a-b)=(24+21)(24-21)=45(3)=135
thus the answer is D
Is This Answer Correct ? | 30 Yes | 1 No |
Answer / harsha
LCM * HCF=product of 2 numbers(a*b)
168*HCF=504
HCF will be 3.
therefore 504 is product of 2 numbers which are multiples of 3..
find out those 2 numbers which are multiples of 3 and their product is 504.
504=2*2*2*3*3*7.=(8*3)*(3*7)
504=24*21...i.e., a=24 ,b =21
difference between products=(24*24)-(21*21)=576-441=135.
Is This Answer Correct ? | 2 Yes | 0 No |
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