Answer / aarti

a.b.c=c.b.a this statement should be inside any program ang
this should give real meaning

Answer / notgate779

http://allinterview.com/showanswers/89174.html
<a
href="http://allinterview.com/showanswers/89174.html">click</a>

Answer / mathu

import java.io.*;

class MainAlpha{
public static void main(String args[])
{
for(int i=65;i<=67;i++){
System.out.printf("%c",i);
System.out.printf("\t");
}
System.out.print("");
for(int j=66;j>=65;j--){
System.out.printf("%c",j);
System.out.printf("\t");
}
System.out.println("");


for(int i=65;i<=66;i++){
System.out.printf("%c",i);
System.out.printf("\t");
}
System.out.print("\t");

for(int j=66;j>=65;j--){
System.out.printf("%c",j);
System.out.printf("\t");
}

System.out.println("");


for(int i=65;i<=65;i++){
System.out.printf("%c",i);
System.out.printf("\t");
}
System.out.print("\t");
System.out.print("\t");
System.out.print("\t");

for(int j=65;j>=65;j--){
System.out.printf("%c",j);
System.out.printf("\t");
}

}

}

Answer / vignesh1988i

good question it is :

#include<stdio.h>
#include<conio.h>
void main()
{
int m;
char n,o;
printf("enter the no. of lines :");
scanf("%d",&m);
o='A';
for(int i=0;i<m;i++)
{
n='A';
for(int j=0;j<(m-i);j++)
printf("%c",n++);
for(j=0;j<i;j++)
printf(" ");
for(j=0;j<(m-(i+1));j++)
{
if(j==0||j==1)
{
n='A'+(m-2);
printf("%c",n);
}
else
printf("%c",--n);
}
printf("\n");
}
getch();
}

thnak u

plssssss help !!....using array.. turbo c.. create a program that will accept number of words to be consored. .a word must not exceed 10 characters long .the text to be entered will be no longer than 200 characters .there will be no 10 words example: enter number of words to be censor: 5 enter words to censor: windows office microsoft bill gates enter text to censor: bill gates founded microsoft and makes office and windows sample output: <consored> <censored> founded <censored> and makes <censored> and <censored>

1 Answers  

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In cryptography, you could often break the algorithm if you know what was the original (plain) text that was encoded into the current ciphertext. This is called the plain text attack. In this simple problem, we illustrate the plain text attack on a simple substitution cipher encryption, where you know each letter has been substituted with a different letter from the alphabet but you don’t know what that letter is. You are given the cipherText as the input string to the function getwordSets(). You know that a plain text "AMMUNITION" occurs somewhere in this cipher text. Now, you have to find out which sets of characters corresponds to the encrypted form of the "AMMUNITION". You can assume that the encryption follows simple substitution only. [Hint: You could use the pattern in the "AMMUNITION" like MM occurring twice together to identify this]

0 Answers   Infosys,

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What are the difference between a free-standing and a hosted environment?

0 Answers   Infogain,

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how to add two numbers without using arithmetic operators?

4 Answers  

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What is c language in simple words?

0 Answers  

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In which category does main function belong??

5 Answers  

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How can I manipulate strings of multibyte characters?

0 Answers  

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12345 1234 123 12 1

2 Answers  

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#include<stdio.h> void main() { int =1; printf("%d%d%d",a++,++a,++a); }

3 Answers   VB,

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int main() { unsigned char a = 0; do { printf("%d=%c\n",a,a); a++; }while(a!=0); return 0; } can anyone please explain me output????

1 Answers  

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why we use pointer in c

7 Answers   HCL, TCS,

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a=10;b= 5;c=3;d=3; if(a printf(%d %d %d %d a,b,c,d) else printf("%d %d %d %d a,b,c,d);

0 Answers   Wilco,

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