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A contractor had employed 100 labourers for a flyover
construction task. He did not allow any woman to work
without her husband. Also, atleast half the men working came
with their wives.
He paid five rupees per day to each man, four ruppes to each
woman and one rupee to each child. He gave out 200 rupees
every evening.
How many men, women and children were working with the
constructor?
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Answer / guest
16 men, 12 women and 72 children were working with the
constructor.
Let's assume that there were X men, Y women and Z children
working with the constructor. Hence,
X + Y + Z = 100
5X + 4Y + Z = 200
Eliminating X and Y in turn from these equations, we get
X = 3Z - 200
Y = 300 - 4Z
As if woman works, her husband also works and atleast half
the men working came with their wives; the value of Y lies
between X and X/2. Substituting these limiting values in
equations, we get
if Y = X,
300 - 4Z = 3Z - 200
7Z = 500
Z = 500/7 i.e. 71.428
if Y = X/2,
300 - 4Z = (3Z - 200)/2
600 - 8Z = 3Z - 200
11Z = 800
Z = 800/11 i.e. 72.727
But Z must be an integer, hence Z=72. Also, X=16 and Y=12
There were 16 men, 12 women and 72 children working with the
constructor.
| Is This Answer Correct ? | 29 Yes | 4 No |
Answer / shiri
answer would be
2omen,with their wifes thats 20
20*5=100
20*4=80
childrn given 1 rupees so
20chidren
| Is This Answer Correct ? | 3 Yes | 19 No |
|3\3 9/9| ! 3["9"" ["39"" | \9/ | ¡ "9""]3 ""9"] YOU "" "" understand this Mssg!! Send
5 Answers Olive Builders, Satyam,
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