Answer / prasoon

#include<iostream.h>
#include<conio.h>
void main()
{
int *p,n,item,pos;
clrscr();
cout<<"\nEnter the number of elements in the array: ";
cin>>n;
p=new int[n+1];
cout<<"\nEnter the elements: \n";
for(int i=0;i<n;i++)
cin>>p[i];
cout<<"\nThe entered elements are: \n\n";
for(i=0;i<n;i++)
cout<<p[i]<<"\t";
cout<<"\nEnter the item to be inserted: ";
cin>>item;
cout<<"\nEnter its position: ";
cin>>pos;
for(i=n;i>=pos;i--)
p[i]=p[i-1];
p[pos-1]=item;
n++;
cout.flush();
cout<<"\nThe modified array is:\n\n";
for(i=0;i<n;i++)
cout<<p[i]<<"\t";
delete p;
getch();
}

Answer / jyoti sur

#include<stdio.h>
#include<conio.h>
void main()
{
int pos,k,n,a[30];
int i;
clrscr();
printf("enter no.of element in array\n");
scanf("%d",&n);
printf("enter the elements\n");
for(i=0;i<n;i++)
{
scanf("%d",&a[i]);
}
printf("your array is:\n");
for(i=0;i<n;i++)
{
printf("%6d",a[i]);
}
printf("\nenter the no.for insertion\n");
scanf("%d",&k);
printf("\n\nenter the position");
scanf("%d",&pos);
--pos;

if(pos<n)
{
for(i=n;i>=pos;i--)

a[i+1]=a[i];
a[pos]=k;
n++;

}
else
printf("\n outside the array");
printf("the new array is:");
for(i=0;i<n;i++)
{
printf("%6d",a[i]);
}
}

Answer / meena

/* Program to insert element into array */
#include<stdio.h>
#include<conio.h>
void main()
{
int arr[50],i,n,pos,num;
clrscr();
printf("How Many Elements:-");
scanf("%d",&n);
printf("\n\tEnter Elements into Array");
for(i=0;i<n;i++)
{
scanf("\t%d",&arr[i]);
}
printf("\nArray Elements before inserting");
for(i=0;i<n;i++)
{
printf("\n%d",arr[i]);
}
printf("\nEnter the position");
scanf("%d",&pos);
if(pos==0 || pos>=n)
{
printf("Invalid position");
}
else
{
printf("\nEnter the number you want to insert into an
array");
scanf("%d",&num);
/*shift the existing elements*/
for(i=n;i>=pos;i--)
arr[i]=arr[i-1];
arr[pos-1]=num;
printf("\nArray elements after insertion");
for(i=0;i<n;i++)
{
printf("\n%d",arr[i]);
}
}
getch();
}

Answer / anupriya garg

#include<iostream.h>
void main()
{
int a[60],n,item,pos;
cout<<"enter the no. of elements in array";
cin>>n;
cout<<"enter the elements";
for(int i=0;i<=n;i++)
{
cin>>a[i];
}
for(int i=0;i<=n;i++)
{
cout<<a[i];
}
cout<<"enter the item to be inserted";
cin>>item;
cout<<"enter the position";
cin>>pos;
for(int i=n;i>=pos;i--)
{
a[i+1]=a[i];
}
a[pos]=item;
n=n+1;
cout<<"the modified array is ;\n\n";
for(int i=1;i<=n;i++)
cout<<a[i];
}

Answer / anupriya garg( sviet)

#include<iostream.h>
void main()
{
int a[60],n,item,pos;
cout<<"enter the no. of elements in array";
cin>>n;
cout<<"enter the elements";
for(int i=0;i<=n;i++)
{
cin>>a[i];
}
for(int i=0;i<=n;i++)
{
cout<<a[i];
}
cout<<"enter the item to be inserted";
cin>>item;
cout<<"enter the position";
cin>>pos;
for(int i=n;i>=pos;i--)
{
a[i+1]=a[i];
}
a[pos]=item;
n=n+1;
cout<<"the modified array is ;\n\n";
for(int i=1;i<=n;i++)
cout<<a[i];
}

Answer / renuka

#include<stdio.h>
#include<conio.h>
void insert(int b[],int n,int pos,int item);
void main()
{
int a[6]={10,20,30,40,50},p,c,item;
printf("enter item and position for insertion");
scanf("%d%d",&item,&p);
printf("array before insertion");
for(c=0;c<=4;c++)
{
printf("%d\n",a[c]);
}
insert(a,6,p,item);
printf("array after insertion");
for(c=0;c<=5;c++)
{
printf("%d\n",a[c]);
}
getch();
}
void(int b[],int n,int pos,int item)
{
int c;
c=n-1;
while(c>pos)
{
b[c]=b[c-1];
c--;
}
b[c]=item;
}

Answer / harini

#include<iostream>
#include<conio.h>
main()
{
int a[5],b,n,e,i,j;
std::cout<<"enter the no of elements:";
std::cin>>n;
std::cout<<"enter the array elements:";
for(i=0;i<n;i++)
{
std::cin>>a[i];
}
std::cout<<"enter the position of insertion:";
std::cin>>b;
std::cout<<"enter the element to be inserted:";
std::cin>>e;
for(j=n;j>b;j--)
{
a[j]=a[j-1];
}
a[j]=e;
std::cout<<"the new array elements are:\n";
for(j=0;j<=n;j++)
{
std::cout<<a[j]<<"\n";
}
getch();
}

Answer / debasmit

#include <stdio.h>

int main()
{
int array[100], position, c, n, value;

printf("Enter number of elements in array\n");
scanf("%d", &n);

printf("Enter %d elements\n", n);

for (c = 0; c < n; c++)
scanf("%d", &array[c]);

printf("Enter the location where you wish to insert an
element\n");
scanf("%d", &position);

printf("Enter the value to insert\n");
scanf("%d", &value);

for (c = n - 1; c >= position - 1; c--)
array[c+1] = array[c];

array[position-1] = value;

printf("Resultant array is\n");

for (c = 0; c <= n; c++)
printf("%d\n", array[c]);

return 0;
}

Answer / sonia

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
main()
{
int a[10]={10,20,30,40,50,60,70,80,90};
int num,i,pos;
printf("enter the no which you want to insert");
scanf("%d",&num);
printf("enter the position");
scanf("%d",&pos);
if(pos<0 || pos>9)
{
printf("invalid position");
getch();
exit(0);
}
for(i=9;i>pos;i--)
a[i]=a[i-1];
a[pos]=num;
for(i=0;i<=9;i++)
printf(" %d",a[i]);
getch();
}

Answer / vinay kumar

#include<iostream.h>
#include<conio.h>
void main()
{ clrscr();
int a[50],i,n,j,p;
cout<<"Enter the size of the array : ";
cin>>n;
cout<<"Enter the elements of the array :\n";
for(i=1;i<=n;i++)
{
cin>>a[i];
}
cout<<"Enter the new element to store : ";
cin>>j;
cout<<"Enter the postion : ";
cin>>p;
a[n+1]=a[p];
a[p]=j;
cout<<"The New series is : \n";
for(i=1;i<=n+1;i++)
{ cout<<a[i]<<"\t";
}
getch();
}

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