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how to convert an char array to decimal array
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#include<stdio.h>
int main()
{
char str[40],*s;
char ch,ask;
do
{
s=str;
printf("Enter the string:");
fgets(str,40,stdin);
do
{
printf("%d ",*s++);
}while(*s);
printf("\nDo u want to enter another string
(y/n):");
ask=getchar();
if(ask=='n')
break;
}while((ch=getchar())!='n');
printf("\n");
}
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / vignesh1988i
#include<stdio.h>
#include<conio.h>
void main()
{
char a1[50];
int a2[50];
printf("enter the characters :");
gets(a1);
for(int i=0;a1[i]!='\0';i++)
a2[i]=(int)a1[i]; // TYPE CASTING
for(i=0;a1[i]!='\0';i++)
printf("%d",a2[i]);
getch();
}
thank you
| Is This Answer Correct ? | 2 Yes | 2 No |
Answer / raj
main()
{
int a[5];
char c[5]={'1','2','3','4','5'};
int i;
for(i=0;i<5;i++)
a[i]=c[i]-'0';
for(i=0;i<5;i++)
printf("%d ",a[i]);
}
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / kanakaraju
#include< stdio.h>
#include<conio.h>
main()
{
int a[5];
char c[5]={'1','2','3','4','5'};
int i;
for(i=0;i<5;i++)
a[i]=c[i]-'0';
for(i=0;i<5;i++)
printf("%d ",a[i]);
}
| Is This Answer Correct ? | 0 Yes | 0 No |
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