main() { intj; while9j<=10) { printf("\n%d",j); j=j+1; } }

main()
{
intj;
while9j<=10)
{
printf("\n%d",j);
j=j+1;
}
}

Question Posted / abdulhamid

4 Answers
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main() { intj; while9j<=10) { printf("\n%d",j); j=j+1; } }..

Answer / ritesh kumar

Since variable j is not initialised it will contain garbage
value hence the output(imposed on the while loop condition)
may be unexpected ..

Is This Answer Correct ?

13 Yes

1 No

main() { intj; while9j<=10) { printf("\n%d",j); j=j+1; } }..

Answer / sathsh

unexpected

Is This Answer Correct ?

3 Yes

3 No

main() { intj; while9j<=10) { printf("\n%d",j); j=j+1; } }..

Answer / soni

compile error

Is This Answer Correct ?

4 Yes

6 No

main() { intj; while9j<=10) { printf("\n%d",j); j=j+1; } }..

Answer / niranjan kumar niraj

output=9

Is This Answer Correct ?

0 Yes

9 No

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