If you started a business in which you earned Rs.1 on the
first day, Rs.3 on the second day, Rs.5 on the third day,
Rs.7 on the fourth day, & so on.
How much would you have earned with this business after 50
years (assuming there are exactly 365 days in every year)?
Answers were Sorted based on User's Feedback
Answer / genius
the ans is 333062500
50 yrs = 50 * 365 = 18250 days
the total earning=1+3+5+7+.......+n
where n=18250
so the sum of arithmetic progression is given by
s= n/2(2a+(n-1)d)
where
s = sum of progression
n = number of terms
a = value of first term
d = difference between 2 terms
so s=(18250/2)(2*1+18249*2)
which gives s=333062500
| Is This Answer Correct ? | 61 Yes | 7 No |
Answer / abhishek gupta
The correct ans. is 333062500
It's given that we work for 50 years, i.e., 50*365= 18250 days.
if we earn Rs.1 on the first day, Rs.3 on the second day,
Rs.5 on the third day & Rs.7 on the fourth day, means we
square the total no. of days to get the total money we
earned. E.g.
In 1 day, we earn Re.1 (squaring 1)
In 2 days, we earn Rs.3+1 (squaring 2) & so on......
So, squaring 18250 , the ans. is 333062500, i.e., we earn
Rs. 333062500 in 50 years= 18250 days.
My ans. has the shortest explanation & cud be called the
best ans. of all the above.
| Is This Answer Correct ? | 22 Yes | 3 No |
Answer / vinod gupta
Let n be the no. of days
Then (n*2)-1 gives us the amount that you earn for that many
days.
Since we need to find for 50 years and each year has 365 days
Thus, n = (365*50) = 18250
Therefore on 50 years you get,
(18250*2)-1 = 36500-1 = 36499
This is the amount you earn on 50 years.
But we need to find the total amount that we would earn
after 50 years.
For this we need to add the amount from day 1 till 50 years
i.e; 18250
Thus we have,
1 + 3 + 5 + 7 + 9 + ... + 36499 = 333062500
Thus after 50 years we have Rs.333,062,500
| Is This Answer Correct ? | 13 Yes | 1 No |
Answer / siddheshwar mali
he ans is 333062500
50 yrs = 50 * 365 = 18250 days
the total earning=1+3+5+7+.......+n
where n=18250
so the sum of arithmetic progression is given by
s= n/2(2a+(n-1)d)
where
s = sum of progression
n = number of terms
a = value of first term
d = difference between 2 terms
so s=(18250/2)(2*1+18249*2)
which gives s=333062500
Thanks for Marking this Answer
Answer / abhishek gupta
The correct ans. is 333062500
It's given that we work for 50 years, i.e., 50*365= 18250 days.
if we earn Rs.1 on the first day, Rs.3 on the second day,
Rs.5 on the third day & Rs.7 on the fourth day, means we
square the total no. of days to get the total money we
earned. E.g.
In 1 day, we earn Re.1 (squaring 1)
In 2 days, we earn Rs.3+1 (squaring 2) & so on......
So, squaring 18250 , the ans. is 333062500, i.e., we earn
Rs. 333062500 in 50 years= 18250 days.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / lava
365*50=18250
sum of n odd no =npwr 2
1+2+3+....upto 18250 terms
so 18250pwr 2=333062500
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / ranjith naidu
let us consider first for 10 days = rs.19=x
next for 20 days =rs.39
and so on
it means for every 10 days itis x+20
in next step x will change that is now x=39
and so on
now in 50 years it will be
((50*365*19)/10)+20)=rs.34695
ans:rs 34695
| Is This Answer Correct ? | 6 Yes | 21 No |
Answer / navpreet singh
50 * 365 = 18250 days
(18250 * 2) - 1 = 36499
| Is This Answer Correct ? | 1 Yes | 16 No |
A number of 9 digits has the following properties: ? The number comprising the leftmost two digits is divisible by 2, that comprising the leftmost three digits is divisible by 3, the leftmost four by 4, the leftmost five by 5, and so on for the nine digits of the number i.e. the number formed from the first n digits is divisible by n, 2<=n<=9. ? Each digit in the number is different i.e. no digits are repeated. ? The digit 0 does not occur in the number i.e. it is comprised only of the digits 1-9 in some order. Find the number.
Your job is to create a simple sum that adds up to 12. You have to use the same number three times and you cannot use the number 4
Everyday in his business a merchant had to weigh amounts from 1 kg to 121 kgs, to the nearest kg. What are the minimum number of different weights required and how heavy should they be?
do you have reference list?
what is the main reason to ask this type question in your interview sir?
Find the least number which when divided by 35, leaves remainder 25; when divided by 45, leaves remainder 35 and when divided by 55, leaves remainder 45.
There is a grid of 20 squares by 10 squares. How many different rectangles are possible? Note that square is a rectangle.
agar aapse wo insaan i love you kahe jis se aap pyar nahi karte to aap uska bina dil dukhaye kya jawab doge?
agar aapne kabhi kisi se saccha pyar kiya hai to is gaane ko complete karo K---N -O --H--T - --G--T---I-A J---N T--S-- S----H--
agar mein aapko ek pen gift du aur aapko kahu ki aap us pen se mere haato me kuch likho jo mujhe hamesa yaad rahe to aap kya likhoge?
justify 1-1=11...
Given a sequence of integers, there are a few sequences which result in balanced binary search trees i.e., AVL trees. Write a program that takes a sequence of integers as input and outputs the number of such sequences that result in the balanced binary search trees. Input Format: Single line contains sequence of integers terminated by -1. Output format: Print the number of AVL tree possible from that input sequence. Sample Input: 1 2 3 -1 Sample Output: 2