Answer / gogol

#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
float a,b,c,x1,x2,disc,disc1;
clrscr();
printf("Let the quadratic equation is of the form:
a(x^2)+b(x)+c=0; Enter the values of the coefficients:\n");
printf("Enter the value of a: ");
scanf("%f",&a);
printf("Enter the value of b: ");
scanf("%f",&b);
printf("Enter the value of c: ");
scanf("%f",&c);
disc=b*b-4*a*c;
if(disc>0)
{
x1=(-b+sqrt(disc))/(2*a);
x2=(-b-sqrt(disc))/(2*a);
printf("The roots are distinct and they are: %3.3f and
%3.3f",x1,x2);
}
if(disc==0)
{
printf("The roots are equal and it is: %3.3f",-b/(2*a));
}
if(disc<0)
{
disc1=-disc;
x1=-b/(2*a);
x2=sqrt(disc1)/(2*a);
printf("The roots are complex and they are: %3.3f+%3.3fi
and %3.3f-%3.3fi",x1,x2,x1,x2);
}
getch();
}

Answer / zainab

#include<conio.h>
#include<stdio.h>
#include<math.h>
void main()
{
int a,b,c;
float d,p,q,r,s;
printf("\n\n Enter the values of a,b,c");
scanf("%d%d%d",&a,&b,&c);
d=(b*b)-(4*a*c);
if(d==0)
{
printf("\n The roots are real and equal");
p=(-b)/(2*a);
q=(-b)/(2*a);
printf("\n The roots of the equation are %f,%f",p,q);
}
if(d>0)
{
printf("\n The roots are real and distinct");
p=((-b)+sqrt((b*b)-(4*a*c)))/(2*a);
q=((-b)-sqrt((b*b)-(4*a*c)))/(2*a);
printf("\n The roots of the equation are %f,%f",p,q);
}
if(d<0)
{
printf("\n The roots are imaginary");
r=(-b)/(2*a);
s=(sqrt((4*a*c)-(b*b)))/(2*a);
printf("\n The roots of the equation are
p=%f+%fi,q=%f-%fi",r,s,r,s);

}
getch();
}

Answer / pamali

gogol y did u use 3.3?

Answer / shubham singh

//program to find roots of given equation
#include<stdio.h>
#include<math.h>
void main()
{
int a,b,c;
float d,p,q,r,s;
printf("\n\n Enter the values of a,b,c")
scanf("%d%d%d",&a,&b,&c);
d=(b*b)-(4*a*c);
if(d=0)
{
printf("\n The roots are real and equal");
p=(-b)/(2*a);
q=(-b)/(2*a);
printf("\n The roots of the equation are %f,%f",p,q);
}
if(d>0)
{
printf("\n The roots are real and distinct");
p=((-b)+sqrt((b*b)-(4*a*c)))/(2*a);
q=((-b)-sqrt((b*b)-(4*a*c)))/(2*a);
printf("\n The roots of the equation are %f,%f",p,q);
}
if(d<0)
{
printf("\n The roots are imaginary");
r=(-b)/(2*a);
s=(sqrt((4*a*c)-(b*b)))/(2*a);
printf("\n The roots of the equation are
p=%f=%fi,q=%f-%fi",r,s,r,s);
}
}

Is the following code legal? struct a { int x; struct a *b; }

2 Answers  

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#include<stdio.h> void fun(int); int main() { int a; a=3; fun(a); printf("\n"); return 0; } void fun(int i) { if(n>0) { fun(--n); printf("%d",n); fun(--n); } } the answer is 0 1 2 0..someone explain how the code is executed..?

1 Answers   Wipro,

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1 Answers  

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main() { int i, j, *p; i = 25; j = 100; p = &i; // Address of i is assigned to pointer p printf("%f", i/(*p) ); // i is divided by pointer p } a. Runtime error. b. 1.00000 c. Compile error d. 0.00000

3 Answers   HCL,

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Write a c program to search an element in an array using recursion

1 Answers   Wipro,

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char *someFun() { char *temp = “string constant"; return temp; } int main() { puts(someFun()); }

1 Answers  

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main() { int x=5; clrscr(); for(;x==0;x--) { printf("x=%d\n”", x--); } } a. 4, 3, 2, 1, 0 b. 1, 2, 3, 4, 5 c. 0, 1, 2, 3, 4 d. none of the above

3 Answers   HCL,

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2 Answers   HCL,

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write a c program to Reverse a given string using string function and also without string function

1 Answers  

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#define int char main() { int i=65; printf("sizeof(i)=%d",sizeof(i)); }

1 Answers  

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what is oop?

3 Answers  

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main(int argc, char **argv) { printf("enter the character"); getchar(); sum(argv[1],argv[2]); } sum(num1,num2) int num1,num2; { return num1+num2; }

1 Answers  

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