Answer / sunil

#include<stdio.h>
#include<conio.h>

char a[10][12]={"one","two","three","four","five","six","seven","eight","nine"};
char b[10][15]={"eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","ninteen"};
char tens[10][15]={"twenty","thirty","fourtey","fiftey","sixty","seventy","eighty","ninty"};

int check(long int num)
{
if(num>10000000)return 5;
if(num>100000)return 4;
else if(num>1000)return 1;
else if(num>100)return 2;
else if(num>10)return 3;
else

return 0;
}

void prnt(long int num,char *s)
{ int n;
if(num<10)
{
printf(" %s %s",a[num-1],s);

}
else if(num>10 && num<20)
{
printf(" %s %s",b[(num-10)-1],s);
}
else if(num>20)
{
printf(" %s ",tens[(num-20)/10]);

n=num%10;
printf(" %s %s",a[n-1],s);
}

}

void main()
{
long int num,n;
int ch=1;

printf("enter no\n");
scanf("%ld",&num);

while( ch!=0)
{

ch=check(num);

// if(ch==0)
// goto l1;

switch(ch)
{
case 1:
n=num/1000;
prnt(n," thousand");
num=num-n*1000;
break;
case 2:
n=num/100;
prnt(n," hundred ");
num=num-n*100;
break;
case 3:
printf(" %s",tens[(num-20)/10]);
num=num%10;
break;
case 4:
n=num/100000;
prnt(n,"lacks");
num=num-n*100000;
break;
case 5:
n=num/10000000;
prnt(n,"crores");
num=num-n*10000000;
break;

}

}
printf(" %s",a[num-1]);
getch();
}

Answer / mayank

/*write a program to accept any number up to five digits and
print that in words(without using array). for example- 1265=
one two six five*/
#include<stdio.h>
#include<stdlib.h>
main()
{
int x,mod, rev=0;
printf("enter number(up to five digits)");
scanf("%d", &x);
if(x>99999)
{
printf("invalid number");
exit(0);
}
while(x>0)
{
mod=x%10;
rev=rev*10+mod;
x=x/10;
}
while(rev>0)
{
mod=rev%10;
switch(mod)
{
case 1:
printf("one ");
break;
case 2:
printf("two ");
break;
case 3:
printf("three ");
break;
case 4:
printf("four ");
break;
case 5:
printf("five ");
break;
case 6:
printf("six " );
break;
case 7:
printf("seven ");
break;
case 8:
printf("eight ");
break;
case 9:
printf("nine ");
break;
case 0:
printf("zero ");
break;
}
rev=rev/10;
}
printf("\n");
}

Answer / rakesh.bit

# include <stdio.h>
int main ()
{
int n,temp,t,s=0,i,ctr=0;
char a[10][10] = {"zero", "one", "two", "three", "four",
"five", "six", "seven", "eight", "nine"};
printf ("Enter the number:\n");
scanf ("%d", &n);
//printf ("The given num in word = %s\n", a[n]);
t=n;
while(n>0)
{
ctr++;
n=n/10;
}
while(t>0)
{
temp=t%10;
s=10*s+temp;
t=t/10;
}

for(i=0;i<ctr;i++)
{
printf("%s",a[s%10]);
s=s/10;
}
}

Answer / sachin patel

#include<stdio.h>
#include<conio.h>
void main()
{
int no;
printf("Enter the no");
scanf("%d",&no);
switch(no)
{
case 1:
printf("One");
break;
case 2:
printf("Two");
break;
case 3:
printf("Three");
break;
case 4:
printf("Four");
break;
case 5:
printf("Five");
break;
case 6:
printf("Six");
break;
case 7:
printf("Seven");
break;
case 8:
printf("Eight");
break;
case 9:
printf("Nine");
break;
default:
printf("You entered Wrong input");
break;
}
}

Answer / siddiqui_1985

i dont have answer i'm actually asking question..

What if we want to print upto nth term??

in a very first post
"


#include<stdioi.h>
void main()
{
int n,count=0,a[20];
scanf("%d",&n);
for(i=0;n>0;i++)
{
a[i]=n%10;
n=n/10;
count++;
}
for(i=0;i<count;i++)
{
switch(a[i])
{
case 1:
printf("one");
break;
case 2:
printf("two");
break;
"

he explicitly doing this using switch case.

Answer / vaibhav dubey

in ans #8,if we,even,reverse the number we can'nt get right
ans in all cases.for example if we enter 1000 than it will
be reversed 0001 and computer will [rint 1 only

Answer / manoj kumar

the program u wrote is wrong because it prints in reverse
means if u gave 12345 the output will be five four three
two one like this
for getting correct output the given number would be
reversed and we write code for that reversed number.

Answer / swathi

# include <stdio.h>
int main ()
{
int n;
char a[10][10] = {"zero", "one", "two", "three", "four",
"five", "six", "seven", "eight", "nine"};
printf ("Enter the number:\n");
scanf ("%d", &n);
printf ("The given num in word = %s\n", a[n]);
}

Answer / vignesh1988i

OK HERE they are asking for 5 digits , but if somewhere
they ask for 'n' digit numbers , then that a[6] wont work
there , Whenever u do a program u will also think of the
worst cases then only we must develop a program...... in all
situations ur program should work!!!!!!!! that's speaks !!

thank u

Answer / prawin62

they directly asks for 5 digit naaa

so read that into a c[6] like that

and print c[0] thousand like that..........

void main() { int a[]={1,2,3,4,5},i; for(i=0;i<5;i++) printf("%d",a++); getch(); }

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