write a c program to print the values in words
eg:- 143 written it has (one hundred and forty three)&
104, 114 are also written words
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Answer / prashant
Sir, i am not able to answer of this program. please send
to me answer of this program.
| Is This Answer Correct ? | 10 Yes | 7 No |
Answer / shameer.k.g
i have seen above this big codeing is not needed because it
is simple program,it need only very less codeing, i have no
time to write ,i have studied this program in
btech,tommorow i have written test for dell
| Is This Answer Correct ? | 1 Yes | 2 No |
Answer / vikas
Can any one help me with this please, I cant get it right. I
have a test on 23/05/2011... Thanks
1
1 2
1 2 3
1 2 3 4
| Is This Answer Correct ? | 0 Yes | 2 No |
Hi,
I have written code for only 3 digit numbers(u may not get
exact result for 100, 200, 113 etc ). This is just for an
idea from which u can build ur logic.
I accept... This code can be optimised.
Dont think that code is too lengthy... cos we hav to hav
limited if, else if or switch for this requirement.
Apply ur logic for 123455677 kind of nos.
#include <stdio.h>
/*Convert no to word... only for 3 digit nos*/
void ConvertToWord(int length);
char* Tens(int *a);
int Temp[10], Length = 0;
int main()
{
int No = 999, DupNo, i, j;
printf("ENTER THE THREE DIGIT NO: ");
scanf("%d", &No);
DupNo = No;
while(DupNo != 0)
{
Temp[Length] = DupNo % 10;
DupNo = DupNo / 10;
Length++;
}
printf("%d - ", No);
ConvertToWord(Length);
_getch();
}
void ConvertToWord(int Length)
{
while(Length != 0)
{
switch(Length)
{
case 0:
break;
case 1:
switch(Temp[Length - 1])
{
case 0:
break;
case 1:
printf("ONE ");
break;
case 2:
printf("TWO ");
break;
case 3:
printf("THREE ");
break;
case 4:
printf("FOUR ");
break;
case 5:
printf("FIVE ");
break;
case 6:
printf("SIX ");
break;
case 7:
printf("SEVEN ");
break;
case 8:
printf("EIGHT ");
break;
case 9:
printf("NINE ");
break;
}
Length--;
break;
case 2:
switch(Temp[Length -1])
{
case 0:
break;
case 1:
break;
case 2:
printf("TWENTY ");
break;
case 3:
printf("THIRTY ");
break;
case 4:
printf("FORTY ");
break;
case 5:
printf("FIFTY ");
break;
case 6:
printf("SIXTY ");
break;
case 7:
printf("SEVENTY ");
break;
case 8:
printf("EIGHTY ");
break;
case 9:
printf("NINETY ");
break;
}
Length--;
break;
case 3:
printf("%s HUNDRED AND ", Tens(&Temp[--
Length]));
break;
}
}
}
char* Tens(int *a)
{
char *ch;
switch(*a)
{
case 0:
ch = "ZERO";
break;
case 1:
ch = "ONE";
break;
case 2:
ch = "TWO";
break;
case 3:
ch = "THREE";
break;
case 4:
ch = "FOUR";
break;
case 5:
ch = "FIVE";
break;
case 6:
ch = "SIX";
break;
case 7:
ch = "SEVEN";
break;
case 8:
ch = "EIGHT";
break;
case 9:
ch = "NINE";
break;
}
return ch;
}
| Is This Answer Correct ? | 3 Yes | 7 No |
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