f(*p) { p=(char *)malloc(6); p="hello"; return; }

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f(*p)
{
p=(char *)malloc(6);
p="hello";
return;
}
main()
{
char *p="bye";
f(p);
printf("%s",p);
}
what is the o/p?

Question Posted / harish

7 Answers
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Hughes, I also Faced
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f(*p) { p=(char *)malloc(6); p="hello"; return; } main() { ..

Answer / fazlur rahaman naik

actually the above programme produces an error.because u've
to mention which type of pointer it is at fuction f(*p).
i.e f(char *p).
if u correct this error.then the out put will be
bye

Is This Answer Correct ?

4 Yes

1 No

f(*p) { p=(char *)malloc(6); p="hello"; return; } main() { ..

Answer / yellareddy

After removing the error, the output is "bye"

Is This Answer Correct ?

0 Yes

0 No

f(*p) { p=(char *)malloc(6); p="hello"; return; } main() { ..

Answer / subbu

after correction of error, the output will be hello

Is This Answer Correct ?

1 Yes

2 No

f(*p) { p=(char *)malloc(6); p="hello"; return; } main() { ..

Answer / vrushali

The answer is bye...

Is This Answer Correct ?

1 Yes

2 No

f(*p) { p=(char *)malloc(6); p="hello"; return; } main() { ..

Answer / hussain reddy

hello

Is This Answer Correct ?

0 Yes

1 No

f(*p) { p=(char *)malloc(6); p="hello"; return; } main() { ..

Answer / madhureddy

the answer is bye

Is This Answer Correct ?

0 Yes

1 No

f(*p) { p=(char *)malloc(6); p="hello"; return; } main() { ..

Answer / vignesh1988i

bye

Is This Answer Correct ?

0 Yes

2 No

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