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how to find that no is int or float?
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Answer / prabhat
if(sizeof(no)==2)
cout<<"Integer";
else if(sizeof(no)==4)
cout<<"Float";
| Is This Answer Correct ? | 5 Yes | 2 No |
Answer / fakkad
incomplete solution.
why? what if no is "long int" or "double"?
in that case his solution will always print float.
| Is This Answer Correct ? | 2 Yes | 0 No |
bool __inline is_integer(float f){
int i = f;
return (f == static_cast<float>(i));
}
int main()
{
int num=0;
double num2= 1234;
num=num2;
if(is_integer(num2))
printf("the number is int");
else
printf("the number is float");
getch();
return 0;
}
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / vignesh1988i
one way according to me is to find through the no. of bytes allocated for that variable or the value itself directly...........
thank u
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / srv
Using sizeof() operator.
if(sizeof(no)==2)
cout<<"no is int";
else
cout<<"float";
| Is This Answer Correct ? | 1 Yes | 4 No |
main() { float a=3.2e40; printf("%d",a); }
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