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what wud be the output?
main()
{
char *str[]={
"MANISH"
"KUMAR"
"CHOUDHARY"
};
printf("\nstring1=%s",str[0]);
printf("\nstring2=%s",str[1]);
printf("\nstring3=%s",str[2]);
a)string1=Manish
string2=Kumar
string3=Choudhary
b)string1=Manish
string2=Manish
string3=Manish
c)string1=Manish Kumar Choudhary
string2=(null)
string3=(null)
d)Compiler error
- 9 Answers
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Answer / rakesh soni
c)string1=Manish Kumar Choudhary
string2=(null)
string3=(null)
Bcoz, at the time of initialization, we are giving "mainsh"
"kumar" "choudhary", which is not comma seprated. so "Manish
kumar choudhary" string goes on to 0 position of the array
of char pointer. rest of 2 string have null.
| Is This Answer Correct ? | 11 Yes | 1 No |
Answer / b subrahmanyam
What does the current output look like this ans is c)
string1=MANISH KUMAR CHOUDHARY
string2=null
string3=null
| Is This Answer Correct ? | 6 Yes | 0 No |
Answer / guruprasad
Compiler Error= Initializer Syntax Error in function main();
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / vijay r15
ans is c
But 1printing mistake in s1 all characters should be in caps
Any dbt mail to raj.vijay55@gmail.com
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / ankush
The answer seems like....
string1=MANISHKUMARCHAUDHARY
string2=(null)
string3=
And curser is blinking after the last line....
ankushtyagi2008@gmail.com
| Is This Answer Correct ? | 1 Yes | 0 No |
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