Answer / ashu

divide the given no by two n store the remainder in stack
and divide again by 2 to quotent the process gong on....
n store all the remainder in the same stack....
n in last pop all the element from stack n print it.

Answer / siddiqui mohd. faisal

It's very simple.
Firstly, the binary no. of 0 is 0000.
After that if you want to know the binary no. of 1 then
jaust add 1 to binary no. of 0 i.e. 0000.So, now the ans
will be 0001.But,remember here 1+1=10.So, now if you want
binary no. of 2 then add 1 to binary no. of 1 i.e. 0001.So,
the binary no. of 2 will be 0010.
I hope you got your question answer.

Answer / vaibhav

divide no. by 2 till 1 is not coming in quotient, then it
write from bottom to top

Answer / santhi perumal

#include<stdio.h>
#include<conio.h>

int main()
{
int i,number;
printf("Enter the Number\n");
scanf("%d",&number);

for(i=7;i>=0;i--)
{
if((1<<i) & number)
printf("1");
else
printf("0");
}
}

Answer / alle balraj

void main()
{
int i,n,p=0,j;
int a[10];
clrscr();
printf("Enter the value of n:\n");
scanf("%d",&n);
i=n;
while(i!=1)
{
if(n==1)
{
a[p]=1;
break;
}
if(n%2==0)
{
a[p]=n%2;
}
else
{
a[p]=n%2;
}
n=n/2;
i=n+2;
i--;
p++;
}
for(j=p;j>=0;j--)
{
printf("%d",a[j]);
}

getch();
}

Answer / bertilla

#include<conio.h>
#include<stdio.h>
void main()
{
int i,n,arr[15];
for(i=0;i<=14;i++){arr[i]=0;}
do
{
arr[i]=n%2;
n=n/2;
i--;
if(n==1){arr[i]=1;}
}while(n>1);
for(i=0;i<=15;i++)
{
printf("%d",arr[i]);
}
getch();
}

Answer / naresh m

main()
{
int a[12],n,m,i=0;
printf("enter the no to find binary no's");
scanf("%d",&n);
while(n!=0)
{
m=i++;
a[i]=n%2;
n=n/2;
}
printf("binary value is");
for(i=m;i>=0;i--)
{
printf("%d",a[i]);
}

Answer / kk

let the number be n
int bin(int n)
{
static int sum=0;

if(n>1)
{
rem=n%2;
sum = sum *10 +rem;
n=n/2;
bin(n);
}
else
{
sum=sum*10+1;
}
return sum;
}

Answer / a.balraj

void main()
{
int i,n,p=0,temp,z;
int a[3];
clrscr();
printf("Enter the value of n:\n");
scanf("%d",&n);
i=n;
while(i!=1)
{
if(n%2==0)
{
temp=n%2;
}
else
{
temp=n%2;
}
a[p]=temp;
n=n/2;
i=n+2;
i--;
p++;
}
for(z=sizeof(a)/sizeof(int);z>=0;z--)
{
printf("%d",a[z]);
}
getch();
}

Answer / subhashini

#include<stdio.h>
#include<conio.h>
{
clrscr();
int i,sum,n;
printf("enter the number");
scanf("%d",&n);
while(n>=1)
{
i=n%2;
sum=sum*10+i;
n=n/2;
getch();
}
printf("the binary number is: %d",i)

the maximum value that an integer constant can have is a) -32767 b) 32767 c) 1.701e+38 d) -1.7014e+38

1 Answers  

write a program which counts a product of array elements lower than 10.

1 Answers  

Explain what is the benefit of using enum to declare a constant?

0 Answers  

Give basis knowledge of web designing ...

0 Answers   HCL,

What is graph in c?

0 Answers  

Which is better pointer or array?

0 Answers  

how many error occurs in C language ?

22 Answers   Infosys, Wipro,

What does the error message "DGROUP exceeds 64K" mean?

0 Answers   Celstream,

Is fortran still used today?

0 Answers  

Is main an identifier in c?

0 Answers  

Question 1: You want to conduct a survey within your classroom, on the quality of canteen’s food. You ask each of your class fellows to rank the quality of food between 1 and 5 (1 representing excellent quality and 5 representing worst quality). During the survey, you make a list containing the roll# of student and the opinion given by that student. The list can be as follow Roll # Opinion 234 1 235 1 236 5 237 1 238 2 239 3 240 5 241 5 242 1 To get the results of the survey, you need to determine the frequency of each opinion value. The frequency of an opinion is determined by counting the number of students giving that opinion. For example, for the above list the frequency of opinion value 1 is 4 and frequency of opinion value 4 is 0. After getting the frequency of each opinion, you can easily judge about the quality of the food by seeing through the frequency of each opinion. You need to develop a program to calculate the results of this survey. The program inputs the opinion of 50 students and counts the frequency of each opinion. It then displays a report showing the frequency of each opinion. Sample output: Opinion Frequency Remarks 1 5 Excellent 2 10 Good 3 15 Normal 4 10 Bad 5 10 Really bad

1 Answers  

the number of measuring units from a arbitrary starting point in a record area or control block to some other point a) branching b) recording pointer c) none d) offset

0 Answers