Answer / dev anand s

select salary from (
select salary, dense_rank() over(order by salary desc) rank from emp) where rank=2;

Answer / rajkishore bagwan

simplest method ----
select salary
from employees
order by salary desc
offset n-1 rows fetch next 1 rows only
(replace n with any number it will give you the nth highest salary)

Answer / hitesh

select top 1 salary from t1 where salary in(select top 2
salary from t1 order by salary desc)order by salary asc

Answer / sabari

select max(salary ) from emp where salary<(select max
(salary)from emp )

Answer / sumit sharma

select sal from (select distinct(sal) from emp where sal is
NOT NULL order by sal dsc) where rownum = 2

Answer / priya

select sal from emp where sal <(select max(sal) from emo)
and rownum<2 order by desc


though rownum which is a pseudo column can be used for
comparisions with relational operators like > or < ,>=, <=
but equalto = may not work in most of the cases..
similarly rowid also.

Answer / nitin umale

SELECT *
FROM employees
WHERE salary =
( SELECT MIN ( r.salary)
FROM ( SELECT salary
FROM ( SELECT DISTINCT salary
FROM employees
ORDER BY NVL(salary,0) DESC
)
WHERE rownum<3) r
);

Answer / abhay

select max(sal) from emp where sal< (select max(sal) from
emp)

Answer / ravi

SELECT TOP 1 salary
FROM (
SELECT DISTINCT TOP n salary
FROM employee
ORDER BY salary DESC) a
ORDER BY salary

where n is the nth highest salary

Answer / dinesh

select * from emp order by sal desc limit 1,1

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