Answer / abhinay

main()
{
int n,m;
do
{
m=n%2;
n=m;
}
while(n>1);
if(m==1)
{
Printf("Number is not a power of 2");
}
else
{
printf("Number is a power of 2");
}
}

Answer / sagar bhagat

#include<stdio.h>
#include<conio.h>
void main()
{
int num,i,flag=0,temp;
clrscr();

printf("\nEnter the number=");
scanf("%d",&num);

if(num<=0)
printf("Plz enter anoter num");
else
{
temp=num;
for(i=1;(i<num) ;i++)
{
if((i*i)==temp)
{
flag=1;
break;
}
}
}
if(flag==1)
printf("\nNumber %d is in power of 2 of %d",num,i);
else
printf("\nNumber %d is not in power of 2 ",num);

getch();
}

Answer / sujan.t

/* 100% correct answer */

int n = 3;
boolean bool = true;
int reminder;
while (n >1)
{
reminder = n % 2;
if(reminder != 0)
{
bool = false;
break;
}
else
{
n = n / 2;
}
}
if (bool == true)
printf("The number is a power of two");
else
printf("The number is NOT A power of two");

Answer / anyone

//Revision for Ahmed Ihmeid answer:
//Operator % prototype: int % int

bool isPowerOf2(int num)
{
int x;

x = num % (int(ceil(sqrt(num)));

if( x == 0)
return true; //it is a power of 2
else
return false; //it is not
}

proof:
4 % 2 = 0
16 % 4 = 0
22 % 5 != 0

Answer / s.v.prasad reddy,lifetree conv

#include<stdio.h>
#include<conio.h>
#include<math.h>
main()
{
int num,i=0,flag;
clrscr();
printf("\nEnter the number:=");
scanf("%d",&num);

if(num==0 || num==1 || (num%2)!=0) /* Validation Part */
{
printf("\n We can't express the given number to power
of 2");
return;
}

for(;;}
{
if(pow(2,i)==num)
{
flag=1;
break;
}
if(pow(2,i)>num)
{
flag=0;
break;
}
i++;
}
if(falg==1)
printf("\n %d number is 2 power of %d",num,i);
else
printf("\n%d number can't be expressed as power of 2",num);

getch();
}

Answer / ahmed ihmeid

bool isPowerOf2(int num)
{
float x;

x = num % (sqrt(num));

if( x == 0)
return true; //it is a power of 2
else
return false; //it is not
}

proof:
4 % 2 = 0
16 % 4 = 0
22 % 4.7 != 0

Answer / hassan noureddine

int isPowrOf2 (unsigned int number)
{
float x;

if (number <= 0) return (0);

x = log(number) / log(2);
return ( (int) ( ((int)x*log(2))/log(number)));
}

Answer / sudhesh

#include<stdio.h>
main()
{
int num,result;
printf("\nEnter the number:=");
scanf("%d",&num);
if (result=num&(num-1))
printf("No\n");
else
printf("Yes\n");
}

Answer / jessu srikanth

int isPowerOf2(unsigned int n)
{
float r=n;
while(r>1) r/=2.0;
return (r==1)?1:0; /* 1-> TRUE; 0-> FALSE*/
}

Answer / sheikh rasel

#include<stdio.h>
main()
{
int i;
if(i%2=0)
printf("The given number is a power of 2");
else
printf("The given number is not a power of 2");
return 0;
}

main() { int x=20,y=35; x = y++ + x++; y = ++y + ++x; printf("%d %d\n",x,y); } what is the output?

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