Answer / ms

int ispow2(int number)
{
if(n<o) {
return 0;
}

else {

return !(number&(number-1));

}

Answer / sivaraj

Answer 2 Ms is correct and more efficient.

because if a number is power 2 it is in form

1000---->8
100----->4
10------>2 like form
subtract one from that and do with bitwise and it should be
zero.

ie 1000(8) & 0111(7)== 0

Answer / abhishek sharma

unsigned int is_power_of_2(unsigned int x)
{
return (x != 0) && ((x & (x - 1)) == 0);
}

Answer / sahil

int ispwrof2(int num)
{
int temp = 0;
if(num <= 0)
return 0;
else if(num > 0)
{
while(num%2 == 0)
{
temp = num/2;
num = temp;

}

}
if(num == 1)
return 1;
else
return 0;
}

Answer / hassan noureddine

To be a power of 2 number,is to have a single 1 bit, and the
rest bits are zeros, lik2 1, 2, 4 , 8, 16, 32, 64, 128, ...

the bitsize of the number is sizeof(number) * 8

isPowerOf2() returns 1 if successful, or 0 (false) otherwise
int isPowerOf2 (number)
{
int foundOnes = 0;
int bitsize = sizeof(number) * 8;

for (i = 0; i < bitsize; i++)
{
if (number & 1)
{
if(++foundOnes > 1)
return false;
/* shift the number to the right */
number >> 1;
}
}
return foundOnes;
}

Answer / santhi perumal

#include<stdio.h>
#include<conio.h>

int main()
{
int i,count = 0,number;

printf("Enter the number\n");
scanf("%d",&number);

for(i=15;i>=0;i--)
{
if((1<<i) & number)
count++;
}

if(count == 1)
printf("\nThe Given Number is Power of 2\n");
else
printf("\nThe Given Number is Not Power of 2\n");

}

Answer / swathi sharma

#include<stdio.h>
int main()
{
int num,i=1;
printf("Enter the number:");
scanf("%d", &num);
do
{
i=i*2;
if(i==num)
{
printf("\n The no.is power of 2.");
break;
}
else if(i>num)
{
printf("\n The no. is not power of 2");
break;
}
}
while(i != num);
return 0;
}

Answer / rajiv malhotra

/* THIS SOLUTION IS 100% CORRECT */

#include<stdio.h>
int isPowerOf2(float n)
{
while(n>1)
{
n/=2.0;
}
return (n==1)?1:0; /* 1-> TRUE; 0-> FALSE*/
}
void main()
{
int x,n;
printf("enter a number\n");
fflush(stdin);
scanf("%d",&n);
x=isPowerOf2(n);
if(x==1)
printf("\n yes");
else
printf("\n no");
}

Answer / sujan

int n = 3;
boolean bool = true;
int reminder;
while (n >1)
{
reminder = n % 2;
if(reminder != 0)
{
bool = false;
break;
}
else
{
n = n / 2;
}
}
if (bool == true)
printf("The number is a power of two");
else
printf("The number "+ m + " is NOT A power of two");

Answer / udhaya

Find if the given number is a power of 2.
//include math.h
void main()
{
int n,logval,powval;
printf("Enter a number to find whether it is s power of
2\n");
scanf("%d",&n);
logval=log(n)/log(2);
powval=pow(2,logval);
if(powval==n)
printf("The number is a power of 2");
else
printf("The number is not a power of 2");
getch();
}

void main() { for(; 0 ;) ... { printf("hello"); ... } getch(); }

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